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2 years ago

Does anybody know this?Find the area of the regular polygon

Mathematics

1 answer:

sweet [91]2 years ago

4 0

Answer:

<h2>2,268 square units</h2>

Step-by-step explanation:

Step 1

Find the area of 1 Triangle

To find this, we will use this formula:

$A=\frac{1}{2} *B*H$

Let's use the formula!

$A=\frac{1}{2} *14*27\\=\frac{1}{2}* 378\\=189$

<em>The area of 1 triangle is 189 square units</em>

Step 2

Find the area of the whole intire shape by multiplying the area of 1 triangle with the amount of sides.

There are 12 sides, so let's multiply 189 by 12

189x12=2268

<h2>Hence, the area of the regular polygon is 2,268 square units</h2>

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What is the greatest common factor of the polynomial's terms?

Alinara [238K]

Step-by-step explanation:

Write the prime factorization of each term:

9r⁵s = 3² × r⁵ × s

6r⁴s² = 2 × 3 × r⁴ × s²

12r²s = 2² × 3 × r² × s

The greatest common factor will have all the common factors raised to their lowest exponent.

So all three terms have 3, r, and s as factors. The lowest exponent of 3 is 1. The lowest exponent of r is 2. The lowest exponent of s is 1.

GCF = 3 × r² × s

GCF = 3r²s

Factor out the GCF:

9r⁵s + 6r⁴s² − 12r²s

3r²s (3r³ + 2r²s − 4)

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3 years ago

A 250-gal tank is initially filled with brine (salt-water mixture) containing 100 lb of salt. Brine containing 3 lb of salt per

gulaghasi [49]

Answer:

x(t) = 581.66 lb

Step-by-step explanation:

From the given information:

Consider the salt quantity in the tank at time t be x(t) lb.

∴ the rate of change of salt content in the tank is $\dfrac{dx}{dt}= Rate \ of \ \ inflow - rate \ of \ \ outflow$

where:

the rate of inflow = salt conc. × flow rate = 3 lb/gallon × 7 gallons

=21 lb/s

rate of outflow = salt conc. in the tank × flow rate

= x/250 × 9

= 9x/250 lb/s

∴

$\dfrac{dx}{dt} = 21 - \dfrac{9x}{250}$

$\dfrac{dx}{dt} + \dfrac{9x}{250}= 21$

This is a 1st order linear differentiation,

The integrating factor if $e^{^{ \int \dfrac{9}{250}\ dt}} = e^{^{ \dfrac{9t}{250} }}$

∴

$e^{^{ \dfrac{9t }{250}}} \ \ x(t) = \int 21 e^{\dfrac{9t}{250}} \ dt + C$

$e^{^{ \dfrac{9t }{250}}} \ \ x(t) = 21 \times \dfrac{250}{9}e^{\dfrac{9t}{250}} + C$

$x(t) = \dfrac{1750}{3}+Ce^{^{\dfrac{-9t}{250}}}$ at t = (0) and x(0) = 100 lb

Hence;

$100 = \dfrac{1750}{3}+C$

$C = \dfrac{1750}{3} -100$

$C = - \dfrac{1450}{3}$

∴ $x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9t}{250}}}$

after time t = 1 minute i.e 60 s

$x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9 \times 60}{250}}}$

$x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-540}{250}}}$

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3 years ago

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Anni [7]

Answer:

B. x=6

move all terms to the left that don't contain x to the right side and solve.

8 0

3 years ago

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What is the value of xy/z if x=-2 and z=4

CaHeK987 [17]

(-2)(y)/4

What is the value of y, I think this is missing to figure out the final answer.

But once y is known you will use the xy/z gormils. Multiply -2 and y value. Then divide that by 4.

Please vote my answer brainliest. thanks!

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son4ous [18]

Answer:

25% i belive

Step-by-step explanation:

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3 years ago