Question

Find the distance between the points (3, 8) and (-1, 9). Round the distance to the nearest hundredth. 3.87 4.12 5.74 2.24

Answer 1

Answer:

≈ 4.12 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (3, 8) and (x₂, y₂ ) = (- 1, 9)

d = $\sqrt{(-1-3)^2+(9-8)^2}$

   = $\sqrt{(-4)^2+1^2}$

   = $\sqrt{16+1}$

   = $\sqrt{17}$

    ≈ 4.12 ( to the nearest hundredth )

Answer 2

Answer:

The distance between given points is: 4.12 units

Step-by-step explanation:

Given points are:

(3, 8) and (-1, 9)

Here

$(x_1,y_1) = (3,8)\\(x_2,y_2) = (-1,9)$

The distance is calculated using the following formula:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Putting the values, we get

$d = \sqrt{(-1-3)^2+(9-8)^2}\\d = \sqrt{(-4)^2+(1)^2}\\d = \sqrt{16+1}\\d = \sqrt{17}\\d = 4.123105...$

Rounding off to nearest hundredth

d = 4.12 units

Hence,

The distance between given points is: 4.12 units