Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Answer:
Step-by-step explanation:
hello :
x² - 6x = 7
x² - 6x+9-9___= 7
(x - 3 )²= __16_
x - 3= +/-_4__
x-3=4__and x-3 =_-4_
Did you mean 9 - 20 will if u did it equals up to -11
For 11a its 2:10 because how you would come up with it is by placing pablos free minutes first and then putting pablos paid minutes and 11b is8:25 because once again you would place sams free minutes first and then his paid minutes
