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Naddik [55]
2 years ago
13

Select the correct answer.

Mathematics
2 answers:
natita [175]2 years ago
5 0

Answer:

B or D but i think its B

Step-by-step explanation:

Radda [10]2 years ago
4 0

Answer:

B

Step-by-step explanation:

In order for something to be a function, they must not have repeating x-values. Looking at the answer choices provided, B is the only answer that does not have repeating x-values.

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Determine the zero of F(x)=x^2+3x-5
IgorLugansk [536]

Answer:

The answer to your question is:

Step-by-step explanation:

                                             x² + 3x - 5

                                    x² + 3x + (3/2)² = 5 + (3/2)²

                                         (x + 3/2)² = 5 + 9/4

                                         (x + 3/2)² = (20 + 9) /4

                                          (x + 3/2)² = 29/4

                                          x + 3/2 = ±√29 / 2

                                     

x 1 = -3/2 + √29/2                               x2 = -3/2 - √29/2

x1 = 1.19                                                x2 = -4.19

3 0
3 years ago
Pleeeeeezzzzzzzz answer this​
zimovet [89]

Answer:49 degrees

Step-by-step explanation: because all the opposite angles are same and alternative angles makes it same too plz mark me brainiest

3 0
3 years ago
Divide and simplify.
balandron [24]
The last one is the correct one.


8 0
3 years ago
What are the answers for both of these what are zeros<br> help
Archy [21]
Graph 5- e)
graph 6- b)
4 0
3 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
lbvjy [14]

Answer:

The equation of the quadratic graph is f(x)= - (1/8) (x-3)^2 + 3 (second option)

Step-by-step explanation:

Focus: F=(3,1)=(xf, yf)→xf=3, yf=1

Directrix: y=5 (horizontal line), then the axis of the parabola is vertical, and the equation has the form:

f(x)=[1 / (4p)] (x-h)^2+k

where Vertex: V=(h,k)

The directix y=5 must intercept the axis of the parabola at the point (3,5), and the vertex is the midpoint between this point and the focus:

Vertex is the midpoint between (3,5) and (3,1):

h=(3+3)/2→h=6/2→h=3

k=(5+1)/2→k=6/2→k=3

Vertex: V=(h,k)→V=(3,3)

p=yf-k→p=1-3→p=-2

Replacing the values in the equation:

f(x)= [ 1 / (4(-2)) ] (x-3)^2 + 3

f(x)=[ 1 / (-8) ] (x-3)^2 + 3

f(x)= - (1/8) (x-3)^2 + 3

4 0
3 years ago
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