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levacccp [35]
2 years ago
14

An employee of a store's gift wrapping center is wrapping 8 gifts

Mathematics
1 answer:
Hitman42 [59]2 years ago
6 0
<h3>Part A:</h3>

The area A of a rectangle is A = bh, where b is the base of the rectangle and h is the height. The area of each rectangle with side lengths 1.5 ft and 2 ft is 1.5 × 2 = 3ft2. Since there are two rectangles with these dimensions, the combined area is 2 × 3 = 6 ft2. The area of each rectangle with side lengths 1.5 ft and 2.5 ft is 1.5 × 2.5 = 3.75 ft2. The area of each rectangle with side lengths 2 ft and 2.5 ft is 2 × 2.5 = 5 ft2. Since there are two rectangles of each type, the combined area is 2 × 3.75 + 2 × 5 =17.5 ft2. <u><em>So, the total surface area of the box is 6 ft2+ 17.5 ft2 = 23.5 ft2</em></u>

<u><em></em></u>

<h3>Part B:</h3>

The employee needs to wrap 8 boxes, each with a surface area of 23.5 ft2. So, the combined surface area needing to be wrapped is 8 × 23.5 = 188 ft2. Since there is only 160 square feet of wrapping paper left, the employee will not be able to wrap all of the gifts

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