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3 years ago

Determinati numerele natrale x care sunt soltii ale incuatiilor:

Mathematics

1 answer:

Studentka2010 [4]3 years ago

6 0

Um.. can you translate that to English..

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Q3. In a hydraulic lift, a 1400 N force is applied to a 0.5 m2 piston. Calculate the minimum surface area of the large piston to

blondinia [14]

Answer:

1.8m^2 approx

Step-by-step explanation:

Given data

P1= 1400N

A1=0.5m^2

P2=5000 N

A2=??

Let us apply the formula to calculate the Area A2

P1/A1= P2/A2

substitute

1400/0.5= 5000/A2

cross multiply

1400*A2= 5000*0.5

1400*A2= 2500

A2= 2500/1400

A2= 1.78

Hence the Area is 1.8m^2 approx

3 0

3 years ago

What is the value of this expresion <br> 4(-6^2+ 3) - 2-1/2

lesya [120]

Answer: -134.5

Step-by-step explanation:

4(-6^2+3) - 2 - 1/2 Exponents first

4(-36 +3) - 2 - 1/2 Now solve the parentheses

4(-33) -2 -1/2

-132- 2 -1/2

-134 - 1/2 = -134.5

7 0

2 years ago

Pls answer question :)

inysia [295]

okay im not sure but maybe try to find a number that can be = to 18 and that might be y

6 0

3 years ago

Read 2 more answers

Xiao teacher asked him to rewrite the sum 60+90 as the product of the GCF of the two numbers and a sum Xiao wrote 3(20+30) what

GrogVix [38]

$The\ mistake:GCF(60;\ 90)\ isn't\ 3\ just\ 30.\\\\Correct\ answer:60+90=30(2+3)$

8 0

2 years ago

Q1.Simplify:

solniwko [45]

$\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\$

$\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\$

$\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625$

6 0

2 years ago

Read 2 more answers