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Sunny_sXe [5.5K]
2 years ago
12

How did the transformation of ()=f of , open x close . equals , x squared to ()=−g of , open x close . equals , x squared , minu

s 3 in part (a) affect the intercepts?
Enter your answer.
Mathematics
1 answer:
Nikolay [14]2 years ago
5 0

The intercepts are the points where the graph crosses the x or y-axis

  • <em>The x-intercepts changed from 0 to </em>\±\sqrt 3<em>.</em>
  • <em>The y-intercepts changed from 0 to  3</em>

The functions are given as:

f(x) = x^2

g(x) = x^2 - 3

<u>Function f(x)</u>

f(x) = x^2

The x-intercept is calculated as follows:

Set f(x) to 0

x^2 = 0

Solve for x

x = 0

The y-intercept is calculated as follows:

Set x to 0

f(0) = 0^2

f(0) = 0

Hence, the intercepts are 0

<u>Function g(x)</u>

g(x) = x^2 - 3

The x-intercept is calculated as follows:

Set g(x) to 0

x^2 - 3 = 0

Solve for x

x^2 = 3

x = \±\sqrt 3

The y-intercept is calculated as follows:

Set x to 0

g(x) = x^2 - 3

g(0) = 0^2 - 3

g(0) = - 3

The x-intercepts are \±\sqrt 3, while the y-intercept is -3

By comparing the intercepts of f(x) and g(x),

  • <em>The x-intercepts changed from 0 to </em>\±\sqrt 3<em>.</em>
  • <em>The y-intercepts changed from 0 to  3</em>

Read more about intercepts at:

brainly.com/question/3334417

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