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user100 [1]
2 years ago
15

Explain the properties of RNA

Biology
2 answers:
Alik [6]2 years ago
7 0

Answer:  The full form of RNA is RIBONUCLEIC ACID and is present mostly in viruses. RNA contains genetic information just like DNA.

Explanation:

masya89 [10]2 years ago
5 0

Answer:

RNA forms in the nucleolus, and then moves to specialized regions of the cytoplasm depending on the type of RNA formed.

RNA, containing a ribose sugar, is more reactive than DNA and is not stable in alkaline conditions. RNA’s larger helical grooves mean it is more easily subject to attack by enzymes.

RNA strands are continually made, broken down and reused.

RNA is more resistant to damage from UV light than DNA.

RNA’s mutation rate is relatively higher.

Unusual bases may be present.

The number of RNA may differ from cell to cell.

Rate of renaturation after melting is quick.

RNA is more versatile than DNA, capable of performing numerous, diverse tasks in an organism.

RNA or ribonucleic acid is a polymer of nucleotides which is made up of a ribose sugar, a phosphate, and bases such as adenine, guanine, cytosine, and uracil.

It is a polymeric molecule essential in various biological roles in coding, decoding, regulation, and expression of genes.

Explanation:

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In trout, Gene A affects body color and yellow color (allele a) is recessive to red. In a particular river system you find that
hjlf

Answer:

The frequency of the dominant A allele is 0,4 or 40%.

Explanation:

In this population, we have:

- "A" red body color Dominant

- "a" yellow doy color Recessive

So, individuals AA and Aa will be red and trouts aa will be yellow.  In this case, 64% of the fish are red, so they are AA or Aa.

If the population is in Hardy-Weinberg equilibrium the following will be true:

p^{2}+2pq+q^{2}=1

Where:

p^{2}=frequency of AA

2pq= frequency of Aa

q^{2}=frequency of aa

It is known that 64% of population is red, in other words:

p^{2}+2pq=0,64

Or AA+Aa=0,64

So, it is possible to find the value of q^{2} (aa):

p^{2}+2pq+q^{2}=1

(0,64)+q^{2}=1

q^{2}=1-0,64q^{2}=0,36

Now, there are two alleles in this population, therefore their frequencies will be:

p+q=1

So, from q^{2} it is possible to find q and p:

q=\sqrt{q^{2} }

q=\sqrt{0,36}

q=0,6

And:

p+q=1\\p=1-q\\p=1-0,6\\p=0,4

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3 years ago
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