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nadya68 [22]
2 years ago
11

Solve the following simultaneous equations in ELIMINATION way​

Mathematics
1 answer:
Allisa [31]2 years ago
3 0

Answer:

Here is the solution...hope it helps:)

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How much fabric is required to cover x buttons in the shape of a circle whose radius is 3x ?
Leviafan [203]

Radius of 1 button = r = 3x

Fabric required to cover 1 button = Area of the circle

= \pi r^{2}

= \pi (3x)^{2}

= 9\pi x^{2}

Total number of buttons = x

Fabric required to cover 1 button = 9\pi x^{2}  

Fabric required to cover x buttons = x(9\pi x^{2} )

=9\pi x^{3}

Hence, fabric required to cover x buttons =9\pi x^{3}  sq. units


3 0
3 years ago
Part A<br> Which net can be folded to make a cube? Select all that apply.
andrezito [222]
Pretty sure it’s ABD
6 0
3 years ago
Read 2 more answers
What is the rule when multiplying or dividing by a negative number to solve inequalities?
Alika [10]
You flip the inequality.
Example: if x > -y and you divide both sides by (-1) then you flip the inequality so: -x < y
4 0
3 years ago
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Match each system to the correct choice.
pogonyaev

Answer:

Option A - Neither. Lines intersect but are not perpendicular. One Solution.

Option B - Lines are equivalent. Infinitely many solutions

Option C - Lines are perpendicular. Only one solution

Option D - Lines are parallel. No solution

Step-by-step explanation:

The slope equation is known as;

y = mx + c

Where m is slope and c is intercept.

Now, two lines are parallel if their slopes are equal.

Looking at the options;

Option D with y = 12x + 6 and y = 12x - 7 have the same slope of 12.

Thus,the lines are parrallel, no solution.

Two lines are perpendicular if the product of their slopes is -1. Option C is the one that falls into this category because -2/5 × 5/2 = - 1. Thus, lines here are perpendicular and have one solution.

Two lines are said to intersect but not perpendicular if they have different slopes but their products are not -1.

Option A falls into this category because - 9 ≠ 3/2 and their product is not -1.

Two lines are said to be equivalent with infinitely many solutions when their slopes and y-intercept are equal.

Option B falls into this category.

8 0
3 years ago
Someone plz help me with this
Phoenix [80]

Answer:

5y^{6}\sqrt{2}

Step-by-step explanation:

We want to  simplify:

\sqrt{50y^{12}}

We rewrite as:

\sqrt{2\times25 \times (y^{6})^2}

We split the radical sign to obtain:

\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}

Simplify the square root for the perfect squares to get:

5y^{6}\sqrt{2}

Therefore the simplified form is: 5y^{6}\sqrt{2}

8 0
3 years ago
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