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3 years ago

What is 0.75 as a percentage

Mathematics

2 answers:

emmasim [6.3K]3 years ago

6 0

75% it is that is the awnser

iren2701 [21]3 years ago

3 0

0.75 as a percentage is 75%, as you move the decimal over one place.

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Hellpppppppppppppppp

VLD [36.1K]

Answer:

15 cups

Step-by-step explanation:

5x3 is 15

even the denominator by multiplying.

do what you multiplied on the numerator.

4 0

3 years ago

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Use distributive property to write an expression that is equivalent to 6(u+12)

nirvana33 [79]

Answer:

6u + 72

Step-by-step explanation:

6(u + 12)

Distribute 6 to u and 12

6(u) + 6(12)

6u + 72

6 0

3 years ago

Answer this question you get 50 points

Sliva [168]

Answer:

Angle YXZ = (1/2) sum of the intercepted arcs

Angle YXZ = (1/2) (41 + 63)

Angle YXZ = (1/2) (104)

Anglw YXZ = 52 degrees

Step-by-step explanation:

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3 years ago

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What is the value of x ?!! Please HELP !!!!!! Will mark BRIANLIEST !!!!!!!!!

Arada [10]

Answer:

Step-by-step explanation:

angles of a triangle always equal 180, so 41 +58=99, so subtract that from 180 and the remaining angle is 81

4 0

3 years ago

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Find the directional derivative of the function at the given point in the direction of the vector v. G(r, s) = tan−1(rs), (1, 3)

alexandr1967 [171]

The <em>directional</em> derivative of $f$ at the given point in the direction indicated is $\frac{5}{2}$ .

<h3>How to calculate the directional derivative of a multivariate function</h3>

The <em>directional</em> derivative is represented by the following formula:

$\nabla_{\vec v} f = \nabla f (r_{o}, s_{o})\cdot \vec v$ (1)

Where:

$\nabla f (r_{o}, s_{o})$ - Gradient evaluated at the point $(r_{o}, s_{o})$ .
$\vec v$ - Directional vector.

The gradient of $f$ is calculated below:

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{\partial f}{\partial r}(r_{o},s_{o}) \\\frac{\partial f}{\partial s}(r_{o},s_{o}) \end{array}\right]$ (2)

Where $\frac{\partial f}{\partial r}$ and $\frac{\partial f}{\partial s}$ are the <em>partial</em> derivatives with respect to $r$ and $s$ , respectively.

If we know that $(r_{o}, s_{o}) = (1, 3)$ , then the gradient is:

$\nabla f(r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{s}{1+r^{2}\cdot s^{2}} \\\frac{r}{1+r^{2}\cdot s^{2}}\end{array}\right]$

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{3}{1+1^{2}\cdot 3^{2}} \\\frac{1}{1+1^{2}\cdot 3^{2}} \end{array}\right]$

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{3}{10} \\\frac{1}{10} \end{array}\right]$

If we know that $\vec v = 5\,\hat{i} + 10\,\hat{j}$ , then the directional derivative is:

$\nabla_{\vec v} f = \left[\begin{array}{cc}\frac{3}{10} \\\frac{1}{10} \end{array}\right] \cdot \left[\begin{array}{cc}5\\10\end{array}\right]$

$\nabla _{\vec v} f (r_{o}, s_{o}) = \frac{5}{2}$

The <em>directional</em> derivative of $f$ at the given point in the direction indicated is $\frac{5}{2}$ . $\blacksquare$

To learn more on directional derivative, we kindly invite to check this verified question: brainly.com/question/9964491

3 0

2 years ago