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Svet_ta [14]
2 years ago
5

Find the y-intercept of the line on the graph. Enter the correct answer.

Mathematics
1 answer:
Wittaler [7]2 years ago
8 0

Check the picture below.

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How can 1/6x − 5 = 1/5x + 2 be set up as a system of equations?
Travka [436]
<span>Given equation = 1/6x – 5 = 1/5x + 2
how can it be set up as linear of equation?
let’s start solving the given equation to show the system of equations:
=> 1/6 x – 5 = y
=> 6y = x – 30
=> 6y – x = -30

=> 1/5 x + 2 = y
=> 5y = x + 10
=> 5y – x = 10

Thus, the system of equation of the given equations are:
=> 6y – x = -30</span><span>
=> 5y – x = 10</span>



7 0
3 years ago
What is the midpoint between 7.2 and 7.3
prohojiy [21]
The midpoint between 7.2 and 7.3 is 7.25, hope this helps
7 0
3 years ago
Solve the inequality | x + 5/3 | -3 &gt; 6
horrorfan [7]

Answer

The solution to the inequality is x > 22/3 or x < -32/3

Explanation

The given inequality is:

|x+\frac{5}{3}|-3>6

The inequality can be solved as follows:

\begin{gathered} |x+\frac{5}{3}|-3>6 \\  \\ Take-3\text{ }to\text{ }the\text{ }other\text{ }side\text{ }of\text{ }the\text{ }inequality\text{ }sign \\  \\ |x+\frac{5}{3}|>6+3 \\  \\ |x+\frac{5}{3}|>9 \end{gathered}

Now, split the absolute value into two inequalities, for case > 9 or < -9

\begin{gathered} x+\frac{5}{3}>9\text{ }or\text{ }x+\frac{5}{3}9-\frac{5}{3}\text{ }or\text{ }x\frac{22}{3}\text{ }or\text{ }x

Hence the solution to the inequality | x + 5/3 | -3 > 6 is x > 22/3 or x < -32/3

5 0
1 year ago
Changing Volume If each edge of a cube is increasing at the constant rate of 3 centimeters per second, how fast is the volume in
timofeeve [1]
Calculus! First one I've seen here! Take the derivative of the volume of a cube. Volume is V = s^3, dV = 3s^2 ds when s = 10 and ds = 3.  I think you used x. Anyway, in the derivative fill in the s with a 10 and the ds (rate of change) is 3. So dV = 3(10)^2 * 3
     dV = 600 cm per second
4 0
3 years ago
The bar graph shows the number of contracts Company X gained each year from 2002 to 2006. Over which of the periods was the aver
vodomira [7]

Answer:

02-04 I think 10+5/2= 12.5 for average

Maybe 02-03 for 10

Step-by-step explanation:

5 0
3 years ago
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