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3 years ago

8

3 teachers share 2 packs of paper equally how much does each teacher get

1 answer:

Alik [6]3 years ago

7 0

How much is in one pack? then add one pack + pack and then divide it by 3

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This is urgent please help me!!

zmey [24]

Answer:

0.1071

Step-by-step exp

6/8 * 5/7 * 4/6 * 3/5 * 2/4 = 0.1071

5 0

4 years ago

Can someone help and explain ? thank you !

AfilCa [17]

$\sf Hello!$

$\sf y = 2x^{2} + 4x - 3$

$\sf Discriminant$ :

= $\sf b^{2} - 4ac$

= $\sf (4)^{2} - 4.(2).(-3)$

= $\sf 16 - (-24)$

= $\sf 16 + 24$ = $\sf 40$

$\sf Since,$
$\sf D \:is\:Greater\: than\: 0.$

$\sf Roots\: are\: Real\: and\: Distinct$

$\sf Hence,$

$\sf y = 2x^{2} + 4x - 3\: have\: A.\: Two\: real\: roots$

~ $\sf iCarl$

7 0

4 years ago

PLS HURRY UP!!!! NEED HELP!!!!

inna [77]

5. Area = 2 unit * 7 units = 14 squared units

6. Area = 3 units * 4 units = 12 square units

7 Area = Area of big rectangle + Area of small rectangle = 42 + 15 = 57 $units^{2}$

8. Area = 1 * 5 + 2*8 = 5 + 16 = 21 square units

Hope that helps!

7 0

2 years ago

Read 2 more answers

>>>>>LOTS OF POINTS<<<<

Lynna [10]

Answer:

4.9 cm

Step-by-step explanation:

To solve this problem you would use the power of a point formula where two chords intersect in the interior of a circle. We get the equation:

7 * 7 = 10 *x

49 = 10x

x = 4.9 cm

6 0

3 years ago

Read 2 more answers

Parallelogram ABCD has vertices at A(2,-3), B(8,-6), Cl14,-3), and D(8,0)

OlgaM077 [116]

Answer:

The correct option is C.

Step-by-step explanation:

The vertices of ABCD are A(2,-3), B(8,-6), C(14,-3), and D(8,0).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of sides are

$AB=\sqrt{(8-2)^2+(-6+3)^2}=\sqrt{36+9}=\sqrt{45}$

$BC=\sqrt{(14-8)^2+(-3+6)^2}=\sqrt{36+9}=\sqrt{45}$

$CD=\sqrt{(8-14)^2+(0-3)^2}=\sqrt{36+9}=\sqrt{45}$

$AD=\sqrt{(8-2)^2+(0+3)^2}=\sqrt{36+9}=\sqrt{45}$

Since length of all sides are equation therefore the given parallelogram cannot be a rectangle.

Slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Slope of AB is

$m_1=\frac{-6-(-3)}{8-2}=\frac{-3}{6}=\frac{-1}{2}$

Slope of BC is

$m_2=\frac{-3-(-6)}{14-8}=\frac{3}{6}=\frac{1}{2}$

Since the slopes of two consecutive sides are not opposite reciprocals, therefore the given parallelogram is a rhombus. Option C is correct.

8 0

3 years ago