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svp [43]
3 years ago
8

3 teachers share 2 packs of paper equally how much does each teacher get

Mathematics
1 answer:
Alik [6]3 years ago
7 0
How much is in one pack? then add one pack + pack and then divide it by 3

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solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0
3 years ago
The local sports shop has backpacks on sale for $28. The original price was $40. What is the percent decrease for the backpack p
emmainna [20.7K]
30%. 40-28 =12. 12/40 =30%
5 0
4 years ago
Determine the length of the leg of a 45o – 45o – 90o triangle with a hypotenuse length of 15 inches. ( ANSWER NEEDS TO BE IN RED
SIZIF [17.4K]

Answer:

The lenghts of both legs: \frac{15\sqrt{2}}{2}\ inches

Step-by-step explanation:

By definition, when a triangle has angles that measures 45°, 45° and 90°, its legs are congruent.

Then, knowing the lenght of the hypotenuse, we can find the lenght (in inches) of  any leg of the given triangle by applying the Trigonometric Identity sin\alpha=\frac{opposite}{hypotenuse}:

sin(45\°)=\frac{leg}{15}\\\\leg=\frac{15}{\sqrt{2}}

Finally, simplifying, we get:

leg=\frac{15(\sqrt{2})}{(\sqrt{2})(\sqrt{2})}=\frac{15\sqrt{2}}{2}

3 0
3 years ago
HELPP ANYBODY KNOW THE ANSWERS TO THE BLANKS IN THE GRAPH?
Margaret [11]

Answer:

5,234

Step-by-step explanation:

4 0
3 years ago
PLZ HELP ME ANSWER THESE FOR BEING THE BRAINLIEST<br> (5a³c/25acpower4)³
VashaNatasha [74]
A^2/5c^3 This is the answer
3 0
3 years ago
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