A segment is bounded by two endpoints.
The two segments can have up to two common points
Assume the line segments are AB and CD where the length of AB is greater than the length of CD.
<u>The possibilities are:</u>
- <em>A point of segment CD lies on segment AB</em>
- <em>Both points of segment CD lie on segment AB.</em>
<em />
See attachment for both possibilities.
Hence, it is possible for the two segments to have two common points.
Read more about line segments at:
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Answer:
Step-by-step explanation:
If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
Answer:
1. 30j+12+6j
2. 36j+12
3. 6(6j+2)
Step-by-step explanation:
1. You just multiply so... 6x5j ... 6x2 ... 6xj
2. you multiply and then simplify so first you have 30j+12+6j, so you add like terms so... 30j+6j= 36j and then +12
3. you do what's in the parentheses first so 5j+j=6j so .... 6(6j+2)
