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sergeinik [125]
3 years ago
6

ALGEBRA 1 PLEASE HELP

Mathematics
1 answer:
solong [7]3 years ago
8 0
Subtract the equations straight down. So we'll subtract the x terms together
5x - 5x = 0x = 0 
meaning the x terms effectively go away after subtraction

Then we do the y terms together in the same exact order
y-3y = -2y

Then finally the right hand side values
6 - (-5) = 6+5 = 11

All of that work done indicates we have 0x-2y = 11 which is the same as -2y = 11. Divide both sides by -2 and we end up with y = -11/2

This answer isn't listed so I'm thinking there's a typo your teacher made somewhere.
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Alex rode 15.5343 miles in his bike

Step-by-step explanation:

1 kilometer is 0.621371 miles, multiply 0.621371 with 25. Hope this helps!

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The inputs of a relation
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4 years ago
For online courses, like those in eCore, there is a positive correlation between the amount of time spent in the course and the
Troyanec [42]

Answer:

Regression Line is given by,

y = 22.909 + 0.209 x

The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436

Step-by-step explanation:

The equation of Regression equation is of the form of:

y = a + bx

where, a is intercept and b is slope

The formula for a and b is given by,

a=\frac{\sum Y \sum X^2-\sum X \sum XY}{n\sum X^2-(\sum X)^2}\\ and, b = \frac{n\sum XY -\sum X \sum Y}{n\sum X^2-(\sum X)^2}

Here, ∑X = 1149.8, ∑Y = 377.2, ∑XY = 93115.95, ∑X² = 320246.72

Thus, a = 22.909

and b = 0.209

Thus, Regression Line is given by,

y = 22.909 + 0.209 x

Thus, The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436

Now plotting these line:

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