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RSB [31]
2 years ago
12

Help with math problem. ​

Mathematics
2 answers:
xxTIMURxx [149]2 years ago
6 0

Answer:


Number of logs:


1. 48


2. 14


3. 90


4. 48


5. 100


Total: 300


Step-by-step explanation:


Just multiply the height with the number of trees then divide by 6. This is in theory if the length of all the trees were conjoined, as there would most likely just be less, then 300. This is because the remainder would be that of the multiplied trees height instead of getting the remainder of wood from each tree. So in case you want to try doing that option, simply divide the height first in feet by 8, then multiply that by the number of trees to give you an accurate answer of logs.


xenn [34]2 years ago
4 0

Answer:

  see attached

  total: 300 logs

Step-by-step explanation:

When calculations are repetitive, it is convenient to let a spreadsheet do them.

Here, the number of logs per tree is found by dividing the tree height by 8 feet. The number of logs from trees that height will be found by multiplying the number of trees by the number of logs that height will give.

The total number of logs is the sum of the numbers from all the tree heights.

__

The total number of logs is 300. (The rightmost column of the attached spreadsheet matches the rightmost column of your table.)

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Dear Laura Ramirez

Answer to your query is provided below

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3 years ago
Oil leaked from a tank at a rate of r(t) liters per hour. the rate decreased as time passed, and values of the rate at two hour
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The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
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4 0
4 years ago
Read 2 more answers
What number makes the expressions equivalent? Enter your answer in the box. 1/2(–1.4m + 0.4) =__m + 0.2A) -1.4B) 1.4C) -0.7D) 0.
Snowcat [4.5K]

Answer:

C. -0.7

Explanation:

Given the equation:

\frac{1}{2}(-1.4m+0.4)=\boxed{\square}_{}m+0.2​

First, distribute the bracket on the left-hand side:

\begin{gathered} \frac{1}{2}(-1.4m)+\frac{1}{2}(0.4) \\ =-0.7m+0.2 \end{gathered}

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The correct choice is C.

6 0
1 year ago
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