<h3>Answer:</h3>
A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°
<h3>Explanation:</h3>
The sum of angles in ∆ABC is 180°, so ...
... (2x -2) + (2x +2) + (5x) = 180
... 9x = 180
... x = 20
and the angles of ∆ABC are ∠A = 38°, ∠B = 42°, ∠C = 100°.
___
The sum of angles of ∆A'B'C' is 180°, so ...
... (58 -x) +(3x -18) +(120 -x) = 180
... x +160 = 180
... x = 20
and ∠A' = 38°, ∠B' = 42°, ∠C' = 100°.
_____
The values of angle measures of ∆ABC match those of ∆A'B'C', so we can conclude ...
... A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°
Answer:
hgkgbnnhm,
Step-by-step explanation:
Hey there!
Your answer is 6n.
"Product of" represents multiplication. So, we can do a number times 6, or "6n".
Have a terrificly amazing day! :D
Answer:
P is exactly 3km east from the oil refinery.
Step-by-step explanation:
Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:
So the cost of laying pipe under water with this distance is
And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:
We can find the minimum value of this by taking the 1st derivative and set it to 0
We can move the first term over to the right hand side and divide both sides by 400000
From here we can square up both sides
d = 3
So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.
Answer:
Option: D is the correct answer.
The equation of line in point-slope form is given by:
y-9=2(x-1)
Step-by-step explanation:
We know that the point-slope equation of a line is given by:
y-b=m(x-a)
where (a,b) is the point from which the line passes and m is the slope of the line.
Here we are given that:
The line passes through (1,9) and slope of the line is given to be 2.
Hence,
(a,b)=(1,9) and m=2
Hence, the equation of line is given by:
y-9=2(x-1)
Therefore, the point slope intercept equation of the line is: D
