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Yuri [45]
3 years ago
9

Finish the steps below to write a quadratic function for the parabola shown. Use the vertex form, f(x) = a(x – h)2 + k, and subs

titute in the values for h and k. f(x) = a(x – 5)2 + 3 Use another point and substitute in values for x and f(x). Solve for a. 5 = a(6 – 5)2 + 3 Write the function, using the values for h, k, and a. The function is f(x) = (x – )2 + .
Mathematics
1 answer:
andriy [413]3 years ago
4 0

Answer:f(x) = a(x – h)² + k

we know the vertex v(5,3)

substitute in the values for h and k

f(x) = a(x – 5)² + 3  

Use another point and substitute in values for x and f(x).  

for the point (6,5)

Solve for a.

5 = a(6 – 5)2 + 3-------------- > 5=a+3-------------> a=2

The function is f(x)=a(x – h)2 + k-------- > 2(x – 5)² + 3

f(x)= 2(x – 5)² + 3-------- > 2[x²-10x+25]+3=2x²-20x+50+3=2x²-20x+53

f(x)=2x²-20x+53

the answer is f(x)= 2(x – 5)² + 3----------------- > (f(x)=2x²-20x+53)

Step-by-step explanation:

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Hi there!

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2.25x + 2.50 = 9.25 would be the equation to represent this scenario.

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Answer:

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Well, it's actually relatively simple.

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