A 40-kilogram mass is moving across a horizontal surface at 5.0 m/s. what is the magnitude of the net force required to bring th
e mass to a stop in 8.0 seconds?
1 answer:
Answer:
25 N
Explanation:
Use the equation F = m(Vf–Vi) / Δt.
average force = mass (final velocity - initial velocity) / change in time
F = 40 kg(5.0 m/s) / 8.0 s = 200 / 8.0 = 25 kgm / s^2 = 25 Newtons
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Answer:
2812.5 N
Explanation:
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F = ma
F = 1875 × 1.5
F = 1875 × 15/10
F = 2812.5 N
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9.50-5=4.50
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