Answer:
x = -3/2 ± i(√11)/2
Step-by-step explanation:
The quadratic formula can be used directly, but I find it convenient to divide by 14 first:
x^2 +3x +5 = 0
The solution to ...
ax^2 +bx +c = 0
is given by the formula ...
x = (-b ±√(b^2 -4ac))/(2a)
Here, we have a=1, b=3, c=5, so the formula gives the solutions ...
x = (-3 ±√(3^2 -4·1·5))/(2·1) = -3/2 ± i(√11)/2 . . . . . solutions are complex
s(4) This means that t = 4, so you can plug in 4 for "t" in the equation
s(t) = 9t - 4
s(4) = 9(4) - 4
s(4) = 36 - 4
s(4) = 32
(4 , 32) This is the point on the graph. To graph it, each unit/square can be 4 [so go by 4's]
3n + 2p
3(6) + 2(2)
18 + 4
22
Answer: 22
*Hope that helps and enjoy Brainly :) *
A quick way to do this is by recalling the fact that
, so the largest value that
alone (for any real value of
) can take on is 1.
This means
, and so
.
So the maximum value of this function is 7.
Answer:
Step-by-step explanation:B) x es un número impar
