Answer:
-5 < x < 9
Step-by-step explanation:
By Hinge theorem,
"If two sides of a triangle are congruent to the two sides of another triangle, and the included angle of one triangle is larger than the included angle of the second, then the 3rd side of triangle one will be larger than the third side of the second"
23 > 21
Therefore, 42° > (3x + 15)°
42° - 15° > 3x
27 > 3x
9 > x
And (3x + 15) > 0
3x > -15
x > -5
Therefore, range for x will be,
-5 < x < 9
Answer:
Alternative hypothesis: "AT LEAST ONE" of the population means is different from the others
Step-by-step explanation:
Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".
The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"
If we assume that we have n groups and we want to check if the population means are equal, th best way to check this it's with an ANOVA test.
The hypothesis for this case are:
Null hypothesis: 
Or in words:
Null hypothesis: All treatments/samples come from populations with the same mean
Alternative hypothesis: Not all the means are equal 
Or we can say:
Alternative hypothesis: "AT LEAST ONE" of the population means is different from the others
Answer:
Step-by-step explanation:
Simply:
Answer:
Well assuming you don’t need to simplify
44/100
0.44
44%
Step-by-step explanation:
Okay so fraction is easy, theres a 100 cubes in total, 44 are shaded in, 44/100 are shaded in which is the area in this scenario.
Decimal is basically moving the place area by a specific amount, in this case theres no whole number since the whole number is 1 or 100/100 and its 44/100 right now so it can’t be a whole number. Decimals go by tenths, hundreths, thousandths, etc. so in this case 44/100 is n the hundreth place since its over a hundred so its 0.44. Or you can move it twice to the right by the times of 0 that appears.
Percent basically means out of 100. So in this case its 44 out of a hundred or 44%
First : x=-5-y and then put x in the phrase above
