Ask question

Ask question

All categories

zloy xaker [14]

3 years ago

8

The ratio of girls to boys in Mr. Smith's homeroom is 3:4. The ratio in Mr. Smith's homeroom to students in the whole 7th grade

is 1:5. The ratio of students in 7th grade to students in the whole middle school is 2:7. If there are 12 girls in Mr. Smith's homeroom, how many students are in the whole middle school?

1 answer:

Leno4ka [110]3 years ago

6 0

3:4 = G:B

1:5 = Mr. Smith's class: 7th Grade

2:7= 7th: Middle school

12 girls = 3 units

1 unit = 12/3= 4

Boys = 4x4= 16

<em>Whole class = 28 students</em>

Class : Grade = 1:5 <em> 7 = number of units in Mr. Smith's class</em>

28 = 1 unit

5 units= 28x5= 140 <em>There are 140 kids in the grade</em>

140 = 2 units

1 unit = 140/2= 70

70x7=490

<u><em>There are 490 students in the whole grade</em></u>

You might be interested in

Dhakdb dnajiden cbsndkfne s

Ainat [17]

That was so sophisticated I pooped myself

5 0

2 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

3 years ago

Read 2 more answers

Matthew bought a suitcase marked down from $90 to $81. What is the discount percentage?

Ksivusya [100]

Answer:

10%

Step-by-step explanation:

Percent change= New-Old |Old|× 100% percent change=81-90 |90| × 100= -9 90×100=-10%

7 0

2 years ago

Andrew McCutchen hit 18 homeruns in 9 baseball games. At this rate, how many homeruns will he have hit

Feliz [49]

Answer:

if it's 18 home runs in 9 baseball games

then you're dividing 18 by 9 which is 2 home runs for every 9 baseball games

to prove if you're right (9×2=18)

if it's 11 baseball games then 11×2=22

Hope It Helps ☺️

6 0

3 years ago

Math help please!

Dovator [93]

Answer:

x || t, [Given]

$m\angle 16 = m\angle 7$ [Given] ......[1]

Transversal defined as a line that cuts across two or more Parallel lines.

When two parallel lines are cut by a transversal, then the pairs of corresponding angles are equal in measure.

$m\angle 16 = m\angle 1$ [Corresponding Angle theorem] ......[2]

Substitute value [1] in [2] we have;

$m\angle 7 =m\angle 1$ [Substitution Property]

When two lines are cut by a transversal and the alternate exterior angles are equal in measure, then the lines are parallel.

k || w [ By Alternative Exterior Angle Theorem] Hence proved!

3 0

2 years ago