Answer:
4. H0: u1= u2 Ha; u1≠ u2
5. The smaller value of p supports the null hypothesis.
Step-by-step explanation:
4. The null and alternate hypotheses are
H0: u1= u2 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1≠ u2 i.e there a difference between the mean pinch strengthof the two surgeries
It can be written like this as well
H0: u1 -u2= 0 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1 -u2≠ 0 i.e there a difference between the mean pinch strengthof the two surgeries
Part 5. The test having a p- value less than 0.05 tells that the null hypothesis cannot be rejected. Theres no evidence to reject the null hypothesis.
The smaller value of p supports the null hypothesis.
(-4-(-7)) / (1-7) = (3) / (-6) = -1/2 = slope
The answer would be +3 since ur adding 3 every time
1) Answer: 21
As y varies directly with x, this means that the ratio y/x is always a constant.
In other words, the equation can be written as y = kx, where k is a constant term.
Thus,
y = 21
2) Answer: C
Exactly the same process as above.
Here's another method:
25 = k(140)
k = 25/140 = 5/28
Thus, when y = 36, 36 = kx
36 = 5/28(x)
36 * 28/5 = x; x = 201.6
3) 9 = k(12)
9/12 = k and k = 3/4
4) On the graph, it hits y = 1 at x = 4.
Thus, we can rewrite the equation as:
y = (1/4)x, where the constant term is 1/4
5) y = kx
The distance represents the x-ordinates, and the time represents the y-ordinates.
9.5/475 = 0.02
4 = 0.02(x), in hours.
x = 200 miles.
The weight of the full steel bead tire in pounds is 1.76 pounds
The weight of the lighter steel bead tire in pounds is 1.54 pounds.
<h3>What are the weights of the tires?</h3>
Division is the process of dividing a number into equal parts using another number. The sign used to denote division is ÷.
The weight of the full steel bead tire in pounds = 800 / 453.592 = 1.76
The weight of the lighter steel bead tire in pounds = 700 / 453.592 = 1.54
To learn more about division, please check: brainly.com/question/13281206
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