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3 years ago

Help from anyone please

Mathematics

1 answer:

Olegator [25]3 years ago

6 0

Find the pattern. 184-164 gets you 20. so 84 - 20 is your answer

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925÷42 in long division

ozzi

The answer would be 22 and a remainder of 1

3 0

3 years ago

Read 2 more answers

Use the identity below to complete the tasks:

quester [9]

Answer:

$a=[2q^{2}r]$

$b=[3s^{2}t]$

Step-by-step explanation:

we have

$8q^{6}r^{3}+27s^{6}t^{3}$

we know that

$8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}$

$27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}$

therefore

$a=[2q^{2}r]$

$b=[3s^{2}t]$

substitute

$a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])$

7 0

3 years ago

Read 2 more answers

What are the measures of angles 1 and 2? R m21 = m22 = 539 U 1 2. 2 S 470 T

Readme [11.4K]

Answer: wala akong alam jan

Step-by-step explanation: makinig ka kasi wag puro brainly

4 0

3 years ago

A random sample of 36 tourists in the Grand Bahamas showed that they spent an average of $1,860 (in a week) with a standard devi

Gnoma [55]

Answer:

$t=\frac{(1860-1935)-0}{\sqrt{\frac{126^2}{36}+\frac{138^2}{64}}}}=-2.76$

Now we can calculate the p value:

$p_v =2*P(t_{98}$

For this case the p value is a very lowe value so then we have enough evidence to reject the null hypothesis. Since the p value is a very low value.

Step-by-step explanation:

Information given

$\bar X_{1}=1860$ represent the mean for Grand Bahamas

$\bar X_{2}=1935$ represent the mean for New Province

$s_{1}=126$ represent the sample standard deviation for Grand Bahamas

$s_{2}=138$ represent the sample standard deviation for New Bahamas

$n_{1}=36$ sample size for the group Grand Bahamas

$n_{2}=64$ sample size for the group New Bahamas

t would represent the statistic

System of hypothesis

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

The statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=36+64-2=98$

The statistic can be calculated like this:

$t=\frac{(1860-1935)-0}{\sqrt{\frac{126^2}{36}+\frac{138^2}{64}}}}=-2.76$

Now we can calculate the p value:

$p_v =2*P(t_{98}$

For this case the p value is a very lowe value so then we have enough evidence to reject the null hypothesis. Since the p value is a very low value.

5 0

3 years ago

Mara found the length of time of an investment. The principal of the investment was $4,300, the interest rate was 6.2 percent, a

77julia77 [94]

well, 6.2% of 4,300 can't be over half. she has made a calculation error, and the real answer is (this is where the mistake was made) 4,300 * 0.062 (not 6.2, because percents are always divided by 100 to make them into a usable number), which is equal to $266.60.

3 0

3 years ago