Answer:
We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 31.7 milligrams
Sample mean,
= 28.5 milligrams
Sample size, n = 9
Alpha, α = 0.05
Sample standard deviation, s = 2.8 milligrams
First, we design the null and the alternate hypothesis

We use One-tailed t test to perform this hypothesis.
Formula:

Putting all the values, we have

Now,
Since,
We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.
200m - 100m + 48,250 = 50,250 - 150m
(Add or subtract common variables)
100m + 48,250 = 50,250 - 150m
(Add 150m to both sides)
250m + 48,250 = 50,250
(Subtract 48,250 to both sides)
250m = 2000
(Divide 250 to both sides to isolate m)
m = 8
One of the angles of a right triangle is always 90 degrees. we have another 13.7 degrees angle. so we can find the other acute angle

the other acute angle measures 76.3
Area = Length x Width
Area = 34 x 14
Area = 476 yd²
Answer: 476 yd²