Answer:B) Archives/backups
Explanation: Archive is the group of records of data that are saved for the future use.These are the historic data that is not currently used in the actual location .
Backup is the the the copy of the group of data that is not in the original form to be used in future. Thus the correct option is option(B).
Updating of the plans by the technician cannot be done through other given options because they don't hold the historic records of the data for the renewing of the plans.
Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
I believe the answer is False or I may be wrong
we translate the following statement given in terms of logarithms. 211 base x can be expressed into log 211 / log x while 152 base 8 can be expressed int o log 152 over log 8. In this case,
log 211 / log x = log 152 / log 8log x = 0.962x = 10^0.962 = 9.1632
Answer:
The program in Python is as follows:
n = int(input("Integer: "))
product = 1
for i in range(1,n+1):
product*=i
if(i!=n):
print(str(i)+" *",end =" ")
else:
print(i,end =" ")
print(" = ",product)
Explanation:
This prompts the user for integer input
n = int(input("Integer: "))
This initializes the product to 1
product = 1
This iterates through n
for i in range(1,n+1):
This multiplies each digit from 1 to n
product*=i
This generates the output string
<em> if(i!=n):</em>
<em> print(str(i)+" *",end =" ")</em>
<em> else:</em>
<em> print(i,end =" ")</em>
This prints the calculated product (i.e. factorial)
print(" = ",product)
