Lack of Computer Expertise. ...
Difficulty Developing Relationships. ...
Privacy and Security Concerns. ...
Issues With Copyrights. ...
Limitations of Business Types.
Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main() {
// variable
int num;
int tot_sum=0;
cout<<"enter a number: ";
// read the value of n
cin>>num;
// check the multiple of 2 or 5 from 1 to n
for(int x=1;x<=num;x++)
{
// if multiple of 2 or 5 then add them
if(x%2==0 ||x%5==0)
{
tot_sum=tot_sum+x;
}
}
// print the sum
cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;
return 0;
}
Explanation:
Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.
Output:
enter a number:11
sum of multiple of 2 or 5 is:35
In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:
#include <stdio.h>
void swaparrayends(int arr[], int nrElements)
{
int temp = arr[0];
arr[0] = arr[nrElements - 1];
arr[nrElements - 1] = temp;
}
void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);
for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
}
getchar();
}
In higher languages like C# it becomes much simpler:
static void Main(string[] args)
{
int[] myArray = {1, 2, 3, 4, 5};
swaparrayends(myArray);
foreach (var el in myArray)
{
Console.Write(el + " ");
}
Console.ReadLine();
}
static void swaparrayends(int[] arr)
{
int temp = arr[0];
arr[0] = arr.Last();
arr[arr.Length - 1] = temp;
}
