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sergiy2304 [10]
3 years ago
8

Answer This question please I need help

Mathematics
1 answer:
Kisachek [45]3 years ago
7 0
457458y236u 12 433236223445568o08y32222333
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What is the equivalent expression of 9+ a J plus 6J -1+ 2K
Salsk061 [2.6K]

Answer:

1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111

Step-by-step explanation:

4 0
3 years ago
A line passes through the point (10,2) and has a slope of 1/2. Write an equation in slope-intercept form for this line.
Natali5045456 [20]

Answer:

Step-by-step explanation:

y - 2 = 1/2(x - 10)

y - 2 = 1/2x - 5

y = 1/2x - 3

4 0
3 years ago
Read 2 more answers
How answer is 49 ?can anyone explain it to me
xz_007 [3.2K]

This chart may seem confusing, but it's not too bad once you get the hang of it. It is known as a mileage chart and it shows the distances between any two cities of this current list.

For example, the distance between Bedford and Cambridge is 29 miles because of the "29" in the very top block. This is the intersection between the "bedford" column and the "cambridge" row. Another example: The distance from Cambridge to Haverhill is 48 miles. Look in the "cambridge" column and the "haverhill" row.

With this in mind, we just need to look at the right rows and columns to find the distances to add up. See the set of attached images below. Figure 1 shows me marking the "cambridge" column and the "royston" row. In this row and column combo is the number 13. So the distance between these two cities is 13 miles.

Then onto figure 2 which shows the distance between Royston and Huntingdon is 21 miles. Figure 3 shows the distance from Huntingdon to Cambridge is 15 miles.

Adding the distances gives: 13+21+15 = 49

So that is why the total round trip distance is 49 miles.

7 0
3 years ago
You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on con
AlladinOne [14]

Using the z-distribution, a sample size of 180 is needed for the estimate.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

In this problem, we have a 98% confidence level, hence\alpha = 0.98, z is the value of Z that has a p-value of \frac{1+0.98}{2} = 0.99, so the critical value is z = 2.327.

The population standard deviation is of \sigma = 23, and to find the sample size, we have to solve for n when M = 4.

Hence:

M = z\frac{\sigma}{\sqrt{n}}

4 = 2.327\frac{23}{\sqrt{n}}

4\sqrt{n} = 2.327 \times 23

\sqrt{n} = \frac{2.327 \times 23}{4}

(\sqrt{n}) = \left(\frac{2.327 \times 23}{4}\right)^2

n = 179.03.

Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
Where do the parentheses go and solve 3×14=3×2×7=3×2×7=×7
grin007 [14]

Answer:

I  don't think this is a real math equation.

Step-by-step explanation:

8 0
3 years ago
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