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yan [13]
2 years ago
5

Display the set of data in a histogram.

Mathematics
1 answer:
Scrat [10]2 years ago
7 0

Answer:

B (The second graph)

Step-by-step explanation:

The order of frequencies of the chart:

1, 13, 9, 8, 12 <em>reference</em>

The order of frequencies of the graphs:

1) 1, 13, 9, 12, 8 <em>incorrect</em>

2) 1, 13, 9, 8, 12 <em>correct</em>

3) 9, 13, 1, 8, 12 <em>incorrect</em>

4) 13, 1, 9, 8, 12 <em>incorrect</em>

Therefore, the second graph 'b', is correct!

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Step-by-step explanation:

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Answer:

\text{tan}(\theta)=\frac{\sqrt{119}}{5}

Step-by-step explanation:

We have been given that Sandra knows the Pythagorean identity \text{sin}^2(\theta)+\text{cos}^2(\theta)=1. She is told that 0\leq \theta\leq \frac{\pi}{2} and \text{cos}(\theta)=\frac{5}{12}.

First of all, we will find value of sine theta using the given identity.

\text{sin}^2(\theta)+\text{cos}^2(\theta)=1

\text{sin}^2(\theta)+(\frac{5}{12})^2=1

\text{sin}^2(\theta)+\frac{25}{144}=1

\text{sin}^2(\theta)+\frac{25}{144}-\frac{25}{144}=1-\frac{25}{144}

\text{sin}^2(\theta)=\frac{144-25}{144}

\text{sin}^2(\theta)=\frac{119}{144}

\text{sin}(\theta)=\sqrt{\frac{119}{144}}

\text{sin}(\theta)=\frac{\sqrt{119}}{12}  

\text{tan}(\theta)=\frac{\text{sin}(\theta)}{\text{cos}(\theta)}

\text{tan}(\theta)=\frac{\frac{\sqrt{119}}{12}}{\frac{5}{12}}

\text{tan}(\theta)=\frac{\sqrt{119}*12}{5*12}=\frac{\sqrt{119}}{5}

Therefore, \text{tan}(\theta)=\frac{\sqrt{119}}{5}.

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