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ruslelena [56]
2 years ago
11

Which term describes BCD

Mathematics
1 answer:
Sphinxa [80]2 years ago
5 0

Check the picture below.

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Find a degree 3 polynomial having zeros -5, 1 and 5 and the coefficient of x^3 equal 1
mote1985 [20]

Answer:

x^3 -x^2 -25x +25

Step-by-step explanation:

\text{The roots are,}~ \alpha  = -5,~ \beta = 1 ~ \text{and}~ \gamma = 5\\\\\text{The polynomial is,}\\\\~~~x^3 - (\alpha + \beta + \gamma)x^2+(\alpha \beta + \beta \gamma+ \gamma \alpha)x - \alpha\beta \gamma\\\\=x^3 - (-5+1+5)x^2 +(-5 \cdot 1 + 1 \cdot 5 + 5 \cdot -5)x - (-5)(1)(5)\\\\=x^3 -(0+1)x^2 + (-5+5-25)x +25\\\\=x^3 -x^2 -25x +25

7 0
2 years ago
I’m not sure with this question help!
labwork [276]

Answer:  C.) 3 to the power of negative two, 1.3 x 10 to the power of negative one, 1/3, and 3 squared.

Step-by-step explanation:

3 to the power of negative 2 = 0.11111111111

3 squared is 1.73205080757

1.3 x 10 to the power of negative 1 = 0.13

1/3 converted to a decimal is 0.333

Now that we know what everything equals we know that anything that doesn't start with 3 squared is right and a little cheat is that only one of them start with 1/3 so we know that the second biggest is 1/3 so it is C.) 3 to the power of negative two, 1.3 x 10 to the power of negative one, 1/3, and 3 squared.

7 0
3 years ago
Read 2 more answers
Find x and h (And show work)
sergey [27]

Answer:

base=×

hypotenuse=6

prependicular=90

we know that

90÷6

×=15

3 0
3 years ago
A train leaves at 1314 and arrives at 1508. It travelled at an average speed of 105 km/h.
Paraphin [41]

Answer: The train traveled 199.5 km

Step-by-step explanation:

We know the relationship:

Distance = Time*Speed

We know that the speed of the train was 105km/h

And we know that it leaves at 13:14, and arrives at 15:08.

Then the total amount of time that the train was traveling is:

T = (15 hours and 8 mins) - (13 hours and 14 mins)

= (15 - 13) hours and (8 - 14) mins

=  2 hours and (-6) mins.

We know that one hour has 60 minutes, then this is equal to:

T = 1 hour and 54 minutes.

But because the speed is kilometers per hour, we need to rewrite the 54 minutes in hours.

This can be done as follows:

1 hour = 60 minutes.

Then: 54 minutes = (54/60) hours = 0.9 hours.

Then:

1 hour and 54 minutes = 1.9 hours.

Now we know the speed and the time, then the distance can be calculated as:

Distance = speed*time = 105km/h*(1.9 h) = 199.5 km

The train traveled 199.5 km

3 0
3 years ago
Read 2 more answers
John's room is shaped like a box. It has a flat ceiling that is a rectangle that is 14 feet long and 8 feet wide and the walls a
erastova [34]
Okay  so John needs to buy 7.6 quarts of paint so he would spend 26.55 on paint.

Hope this helps:)

6 0
3 years ago
Read 2 more answers
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