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2 years ago

Find the missing angle. 90 - 43 y = [???]

Mathematics

1 answer:

Stella [2.4K]2 years ago

6 0

Step-by-step explanation:

Here. ...the sum of interior angle of triangle is 180° so...

90° + 43° + y = 180°.

133° + y = 180°

y = 180° - 133°

y = 47°

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Help please!!!!!!!!!!!!!

Natali [406]

I think it’s F I’m not sure if it’s correct !

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3 years ago

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During the half time of a basketball game, a sling shot launches T-shirts at the crowd. The T-shirt is launched with an initial

kumpel [21]

Step-by-step explanation:

The T-shirt is launched with an initial upward velocity of 60 ft/s from a height of 5 feet. Its equation of motion is given by :

$f(x) = -12x^2 + 60x + 5$ ....(1)

(a) For maximum height, put $\dfrac{df(x)}{dt}=0$

So,

$\dfrac{ d(-12x^2 + 60x + 5)}{dt}=-24x+60$

Now put,

$-24x+60=0\\\\x=2.5\ s$

So, the time taken for the T-shirt to reach maximum height is 2.5 seconds.

(b) Put x = 2.5 s in equation (1)

$f(x=2.5) = -12(2.5)^2 + 60(2.5) + 5\\\\f(x)=80\ \text{feet}$

8 0

3 years ago

Answers with links will be reported

Ber [7]

Answer:

11 months

Step-by-step explanation:

the math that i did was i kept adding 400 to 2500 and counted every four hundred that i added witch was 11 until i got to 7000 so the answer is 11 months. You will have some left over which you will have 300 left over.

8 0

2 years ago

Solve the system of equations by graphing or using a table <br> 3x+ y= 5 <br> x -y = 7

kobusy [5.1K]

Its supposed to be 3x+y=5 x-y=2

6 0

2 years ago

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Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago