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den301095 [7]
3 years ago
11

A rental car costs $65 for one day plus and additional fee costing $0.35 a mile. What is the cost for renting a car for one day

and driving it 115 miles? What is the equation?
Mathematics
1 answer:
Advocard [28]3 years ago
4 0

Answer:

Part a = 105.25 Part b 65 + 0.35x

Step-by-step explanation:

65 is the money you have to spend to rent it for one day. and 0.35 is the cost per mile. 115 x 0.35 = 40.25.

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6.Find the equation of<br> the line:<br> through: (-2, 3) and<br> (1,5)
prohojiy [21]

Answer:

y=2/3x+4.3

Step-by-step explanation:

y=mx+c

(5-3)/(1--2)

2/3= gradient

y=2/3x +c

5=2/3(1)+c

-2/3

4.3=c

6 0
3 years ago
a group of 60 children went on a trip to the zoo 7/10 of the children had never been there how many children went to the zoo for
zvonat [6]

Answer:

42

Step-by-step explanation:

as you divide 10 into 60 and then multiply it by 7 and your answer will be 42

5 0
3 years ago
What is the distance between point A(-3,2) and point B(5,-1)
Gnoma [55]

Remember the distance formula

S=\sqrt{(5+3)^{2}+(-1-2)^{2} }

S=\sqrt{8^{2}+(-3)^{2} }

S=\sqrt{64+9}

S=\sqrt{73}


8 0
3 years ago
Solve for X. Leave your answer in simplest radical form if necessary.
lord [1]

:) Brainliest?

Answer:

x = sqrt 2, y = 2

Step-by-step explanation:

45-45-90 triangles have a ratio of 1 : 1 : sqrt2

8 0
3 years ago
Read 2 more answers
See question in screenshot below.
alexgriva [62]

The equation of the transformation of the exponential function <em>y</em> = 2ˣ in the form <em>y</em> = A·2ˣ + k, obtained from the simultaneous found using the points on the graph is <em>y</em> = (-2)·2ˣ + 3

<h3>What is an exponential equation?</h3>

An exponential equation is an equation that has exponents that consists of variables.

The given equation is <em>y</em> = 2ˣ

The equation for the transformation is; <em>y</em> = A·2ˣ + k

The points on the graphs are;

(0, 1), (1, -1) and (2, -5)

Plugging the <em>x </em>and <em>y</em>-values to find the value <em>A</em> and <em>k</em> gives  the following simultaneous equations;

When <em>x</em> = 0, <em>y</em> = 1, therefore;

1 = A·2⁰ + k = A + k

1 = A + k...(1)

When <em>x</em> = 1, <em>y</em> = -1, which gives;

-1 = A·2¹ + k

-1 = 2·A + k...(2)

Subtracting equation (1) from equation (2) gives;

-1 - 1 = 2·A - A + k - k

-2 = A

1 = A + k, therefore;

1 = -2 + k

k = 2 + 1 = 3

k = 3

Which gives;

y = -2·2ˣ + 3 = 3 - 2·2ˣ

Learn more about the solutions to simultaneous equations here:

brainly.com/question/26310043

#SPJ1

3 0
1 year ago
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