Answer: 46.08 kg
Answer:
Step-by-step explanation:
Theres probably a better solution but brute force is sometimes good enough
Answer:
the answer is smallest to biggest
Step-by-step explanation:
Answer:
∠RST = 120°
Step-by-step explanation:
We assume the positions of the lines and angles will match the attached figure. The angle addition theorem gives a relation that can be solved for x, then for the value of angle RST.
∠RSU +∠UST = ∠RST
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78° + (3x -12)° = (6x +12)° . . . . . substitute given values into the above
54 = 3x . . . . . . . . . . . . . . . . divide by °, subtract 3x+12
108 = 6x . . . . . . . . . . . multiply by 2
120° = (6x +12)° = ∠RST . . . . add 12, show units
The measure of angle RST is 120 degrees.
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<em>Additional comment</em>
Note that we don't actually need to know the value of x (18) in this problem. We only need to know the value of 6x.
Answer:
x > -3 and x ≤ 1
Step-by-step explanation:
[First inequality]
Given:
-2x + 8 < 14
Subtract 8 from both sides:
-2x < -6
Divide both sides by -2, since it's negative we also flip the sign:
x > 3
[Second inequality]
Given:
-3x - 9 ≥ -12
Add 9 to both sides:
-3x ≥ -3
Divide both sides by -3, since it's a negative we also flip the sign:
x ≤ 1
Length = L
New length = L+0.1L= 1.1 L
Width = W
New width = W - (W/100)p= W-pW/100= (100W-pW)/100=W(100-p)/100
Area =A = LW
New area = A - 0.12A = 0.88A
New area = new width*new length = 1.1L*W(100-p)/100 = 1.1A(100-p)/100
New area = 0.88A
New area = 1.1A(100-p)/100
1.1A(100-p)/100 = 0.88A
1.1(100-p)/100 = 0.88
1.1(100 - p) = 88
100 - p = 80
p = 20
Answer C) 20.