A boat in calm seas travels in a straight line and ends the trip 22 km west and 53 km north of its original position. To the nea
rest tenth of a degree, find the direction of the trip
2 answers:
<span> By tangent function... </span>
<span>tan(x) = 22/53 </span>
<span>x ≈ 23° Hope This Helps</span>
So the end pt is 22km west n 53km north so the angle = arctan(22/53) = 22.5 degree
So the direction is North 22.5deg West
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Answer:
23.64
Step-by-step explanation:
× (2 - 5)² + 6
= × (- 3)² + 6
= 1.96 × 9 + 6
= 17.64 + 6
= 23.64
Yea I don’t knowing how to help you please explain
X² + x + ...m
x² + x + 1/4
\/x² = x
\/(1/4) = 1/2
2*x*1/2 = 2x/2 = x
x² + x/2 + 1/4
I believe x=-1.2 because
when you get that answer divided 0.875x by that answer
Answer:
9.00
Step-by-step explanation: