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2 years ago

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A bicycle store costs $2200 per month to operate. The store pays an average of $40 per bike. The average selling price of each b

icycle is $80. How many bicycles must the store sell each month to break even?

1 answer:

sergey [27]2 years ago

4 0

Answer:

Step-by-step explanation:

120n=2400+60n is break-even point

60n=2400

n=40 bikes need to be sold monthly to break even!!!!!!!!!!!!

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3 years ago

Which of the following is a pair of vertical angles ?

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4 years ago

Read 2 more answers

A bicycle store costs $3500 per month to operate. The store pays an average of $75 per bike. The average selling price of each

vfiekz [6]

Answer: the store needs to sell 50 bicycles each month to break even

Step-by-step explanation:

The average selling price of each bicycle is $145.

When we talk of break even, we are referring to the point at which the income being accrued from a business is equal to the total cost of running the business. At this point, their is no profit and there is no loss.

From the example information given,

Total cost of running the business will be

cost of operating the bicycle store + the total amount the store pays per bike.

cost of operating the bicycle store

= $3500 per month

The store pays an average of $75 per bicycle. If the store buys x bicycles per month, then,

Total the total amount the store pays per bike = 75 × x = 75x

Total cost of running the business per month

= 3500 + 75x - - - - - - -1

The average selling price of each bicycle is $145. This means that the selling price for x bicycles will be

145 × x = 145x

Therefore , total income is $145x

To break even,

145x = 3500 + 75x

145x - 75x = 3500

70x = 3500

x = 3500 / 70 = 50

8 0

3 years ago

Find the measure of angle A.<br> A<br> 7x-1<br> 12x<br> 489

Degger [83]

Answer:

48 degrees

Step-by-step explanation:

7X-1+12x+48=180

19x+47=180

19x=133

x=7

7(7)-1=A

49-1=A

48=A

A is 48 degrees

7 0

3 years ago

It is estimated that 75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell

Mademuasel [1]

Answer:

a) 75

b) 4.33

c) 0.75

d) $3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline

e) $6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with $n = 100, p = 0.75$

g) $4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that $p = 0.75$

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so $n = 100$

$E(X) = np = 100(0.75) = 75$

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33$

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}$

$3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}$

$6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with $n = 100, p = 0.75$

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}$

$4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

8 0

3 years ago