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3 years ago

How many solutions does the system of equations have?

1 answer:

3 0

First, simplify this system:

2x = -10y + 6 and x + 5y = 3

by dividing the first equation by 2. Result: x = -5y + 3

Subbing this into the 2nd equation, -5y + 3 + 5y = 3

This equation is always true, so this system has infinitely many sol'ns.

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Standard Form: 3x+4y=−16

Gnesinka [82]

Answer:

i know the answer

Step-by-step explanation:

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2 years ago

Why is this simplified by combining like terms 3(4x+5) +2

Inga [223]

3(4x+5)+2
3•4x=12x
5•3=15+2=17
Answer= 12x + 17

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2 years ago

Which angles are corresponding angles?

FromTheMoon [43]

Answer:

D, E, F, C,

Step-by-step explanation:

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3 years ago

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Determine if A^-1 C=C A^-1 Given: A^-1 C=

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CA ⁻¹ is undefined because there are more columns in A ⁻¹ than there are rows in C.

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2 years ago

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Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.

lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

$PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ$

Likewise:

$\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ$

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

$m\angle PAC=m\angle PAB+m\angle BAC$

Likewise:

$m\angle QAB=m\angle QAC+m\angle BAC$

Since ∠QAC ≅ ∠PAB:

$m\angle PAC=m\angle QAC+m\angle BAC$

And by substitution:

$m\angle PAC=m\angle QAB$

Thus:

$\angle PAC\cong \angle QAB$

Then by SAS Congruence:

$\Delta PAC\cong \Delta BAQ$

And by CPCTC:

$PC\cong BQ$

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2 years ago

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