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alex41 [277]
3 years ago
15

Plz help i will report if your not trying to answer​

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0
1) 1 x 10^4
2) 1 x 10^0
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A 4-digit PIN number is selected. What it the probability that there are no repeated digits?
geniusboy [140]

Answer:

P(A)=0.504 or 50.4%

Step-by-step explanation:

The <em>probabilities</em> constitute a branch of mathematics that deals with measuring or quantitatively determining the possibility that an event or experiment produces a certain result. The probability is based on the study of combinatorics and is the necessary foundation of statistics.

A <em>permutation</em> is an ordered arrangement of objects in a group, without repetitions.

A 4-digit PIN is selected. What is the probability that there are no repeated digits?

First, there are only 10 possible values for each digit of the PIN (0, 1, 2, 3, 4, 5, 6, 7, 8, 9). The total possibles 4 PINs are 10^{4} =10000

There's no repeated numbers and all the four numbers have to be different, which means we have to select 4 numbers out of 10 numbers. Using the permutation equation nP_{k} =\frac{n!}{(n-k)!}

10P_{4} =\frac{10!}{(10-4)!}=10.9.8.7.6= 5040

So, the probability that there are no repeated digits is:

P(A)=favorable cases/possible cases

P(A)=\frac{5040}{10000}=0.504 or 50.4%

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4 years ago
Simplify.<br> √3(√6+√15)
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Answer:

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A. (5,8)
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D: Both the slopes and the y-intercepts are the same.

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Domain is numbers you can use
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domain=all real numbers greater than or equal to 0
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