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1 year ago

Pascal's Triangle

Mathematics

1 answer:

tiny-mole [99]1 year ago

4 0

Answer:

isk but i think u need to multiply

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Vinvika [58]

Isn't the answer, 3 1/2

6 0

3 years ago

Geometry question please help, any help is appreciated!

raketka [301]

Equation of the circle is
(x-h)² + (y-k)² = r²,

where (h, k) are coordinates of the center of the circle.
(h,k)= (0,-2)
radius r= 6

(x-0)² +(y-(-2))²=6²

x² + (y+2)² = 36

6 0

3 years ago

In 17, 874,000 what is the value of 1

artcher [175]

Answer:

<h2>Ten Millions</h2>

Step-by-step explanation:

1 = Ten Millions

7 = Millions

8 = Hundred Thousands

7 = Ten Thousands

4 = Thousands

0 = Hundreds

0 = Tens

0 = Ones

Hope this helps! <3

4 0

3 years ago

Divide 6⁄13 by 6⁄12 . <br><br> A. 1⁄12<br> B. 9⁄16<br> C. 12⁄13<br> D. 13⁄12

nadezda [96]

6/13÷6/12=12/13 so C.

Hope this helps!

5 0

2 years ago

Read 2 more answers

The linear equation y = mx + b contains the point (4, -2) and is perpendicular to the

xenn [34]

A linear equation is represented as: $y = mx + b$ .

The equation of the line is: $y =3x - 14$

First, we calculate the slope (m) of $6x + 18y = 11$

Make y the subject

$18y = -6x + 11$

Divide by 18

$y = -\frac{1}{3}x + \frac{11}{18}$

In $y = mx + b$

$m \to$ slope

So, the slope of $y = -\frac{1}{3}x + \frac{11}{18}$ is:

$m = -\frac 13$

Since, the line is perpendicular to $6x + 18y = 11$

The slope of the line is:

$m_1 = -\frac{1}{m}$

So, we have:

$m_1 = -\frac{1}{-1/3}$

$m_1 = 3$

The line passes through (4,-2).

So, the equation is:

$y =m(x - x_1) + y_1$

This gives:

$y =3(x - 4) -2$

$y =3x - 12 -2$

$y =3x - 14$

Hence, the linear equation is:

$y =3x - 14$