N/5 = 6/7 we have to cross multiply to solve each proportion of solve for n

In how many years will $ 21,136.18 amount to $ 75,514.55 at 27.54 % per annum when compounded quarterly?

qaws [65]

The number of years is 4.781 in which $21,136.18 amount to $75,514.55 at 27.54% per annum when compounded quarterly and this can be determined by using the formula of the compound interest.

Given :

Principal amount = $21136.18
Final amount = $75514.55
Interest rate per annum = 27.54%
Compounded quaterly.

The formula of the compound interest is given by:

$\rm A= P(1+\dfrac{r}{n})^{nt}\\$

where A is the final amount, P is the principal amount, r is the interest rate, t is the time in years, and 'n' is a number of times interest applied.

Now, substitute the values of known terms in the above formula.

$\rm 75514.55= 21136.18(1+\dfrac{0.2754}{4})^{4\times t}\\$

$3.5727=(1.06885)^{4t}$

Now, take the log on both sides.

$\rm log(3.5727)=(4t)log(1.006885)$

19.1237 = 4t

t = 4.781 years

Therefore, the correct option is B).

For more information, refer to the link given below:

brainly.com/question/14295570

3 0

3 years ago

Read 2 more answers

2+2= ???????<br><br> Will give brainlyest answer!!!!!!

Alex17521 [72]

Answer: fish

Step-by-step explanation: 2+2=fish

6 0

3 years ago

Find, correct to the nearest degree, the three angles of the triangle with the given ven

Scrat [10]

9514 1404 393

Answer:

∠CAB = 86°

∠ABC = 43°

∠BCA = 51°

Step-by-step explanation:

This can be done a couple of different ways (as with most math problems). We can use the distance formula to find the side lengths, then the law of cosines to find the angles. Or, we could use the dot product. In the end, the math is about the same.

The lengths of the sides are given by the distance formula.

AB² = (4-1)² +(-3-0)² +(0-(-1)) = 16 +9 +1 = 26

BC² = (1-4)² +(2-(-3))³ +(3-0)² = 9 +25 +9 = 43

CA² = (1-1)² +(0-2)² +(-1-3)² = 4 +16 = 20

From the law of cosines, ...

∠A = arccos((AB² +CA² -BC²)/(2·AB·CA)) = arccos((26 +20 -43)/(2√(26·20)))

∠A = arccos(3/(4√130)) ≈ 86°

∠B = arccos((AB² +BC² -AC²)/(2·AB·BC)) = arccos((26 +43 -20)/(2√(26·43)))

∠B = arccos(49/(2√1118)) ≈ 43°

∠C = arccos((BC² +CA² -AB²)/(2·BC·CA)) = arccos((43 +20 -26)/(2√(43·20)))

∠C = arccos(37/(4√215)) ≈ 51°

The three angles are ...

∠CAB = 86°

∠ABC = 43°

∠BCA = 51°

_____

<em>Additional comment</em>

This sort of repetitive arithmetic is nicely done by a spreadsheet.

6 0

3 years ago

What is the solution of the equation? 2^5 sqrt (x+6)^3 +3 =19

EleoNora [17]

I got that x=-5.37003947. I am not sure that I put everything under the square root that needed to be there so I hope this helps.

3 0

3 years ago

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Solve the given equation: 2 x ( x + 3 ) − 6 ( x + 3 ) = 0 2 x ( x + 3 ) - 6 ( x + 3 ) = 0

vitfil [10]

Answer:

x = 3 or x = -3

Step-by-step explanation:

Solve for x over the real numbers:

2 x (x + 3) - 6 (x + 3) = 0

Expand out terms of the left hand side:

2 x^2 - 18 = 0

2 x^2 - 18 = 2 (x^2 - 9):

2 (x^2 - 9) = 0

Divide both sides by 2:

x^2 - 9 = 0

x = (0 ± sqrt(0^2 - 4 (-9)))/2 = ( ± sqrt(36))/2:

x = sqrt(36)/2 or x = (-sqrt(36))/2

sqrt(36) = sqrt(4×9) = sqrt(2^2×3^2) = 2×3 = 6:

x = 6/2 or x = (-6)/2

6/2 = 3:

x = 3 or x = (-6)/2

(-6)/2 = -3:

Answer: x = 3 or x = -3

6 0

3 years ago