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koban [17]
3 years ago
9

4. What is the area of the circle below? 3m

Mathematics
2 answers:
notsponge [240]3 years ago
4 0

Answer:

π∗9 or 28.28

Step-by-step explanation:

With the equation of A = \pi * r^2A=π∗r

2

, We find that the r - (radius) = 3, so it would be \begin{gathered}\pi *3^2\\\end{gathered}

π∗3

2

stealth61 [152]3 years ago
3 0

Answer:

\pi * 9 or 28.28

Step-by-step explanation:

With the equation of A = \pi * r^2, We find that the r - (radius) = 3, so it would be \pi *3^2\\ or \pi * 9

Hope This Helps!

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If BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6, what are the values of x and AC?
Keith_Richards [23]

Answer: x=7 and AC = 44 unuts.

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other. (i)

Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.

BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6

Using (i)

BE=\dfrac{BD}{2}\\\\2x+2=\dfrac{5x-3}{2}\\\\ 2(2x+2)=5x-3\\\\ 4x+4= 5x-3\\\\ 5x-4x=4+3\\\\ x= 7

Now , AE = 4(7)-6 = 28-6 = 22

AC =2 AE = 2 (22) =44 units.

Hence, x=7 and AC = 44 unuts.

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Step-by-step explanation:

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A meat inspector has randomly selected 30 packs of 95% lean beef. The sample resulted in a mean of 96.2% with a sample standard
kirza4 [7]

Answer:

a

 The upper bound of the 99% prediction level is 98.2  

b

 The  95% confidence interval is 9.7383 <  \mu < 10.2617

Step-by-step explanation:

Considering first question

From the question we are told that

   The sample size is  n  =  30  

   The sample mean is  \= x  =  96.2\%

   The standard deviation is s  = 0.8\%

Generally the degree of freedom is mathematically represented as

        df  =  n - 1

=>      df  =  30 - 1

=>      df  =  29

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the t distribution table the critical value  of   at a degree of freedom of is  

   t_{\alpha , 29} = 2.462

Generally the  99%  prediction level is mathematically represented as

      \= x \pm [(t_{\alpha  , df }) * s * (\sqrt{1 + \frac{1}{ n} } )}]

Generally the upper bound of the 99%  prediction level is mathematically represented as

      \= x + [(t_{\alpha  , df }) * s * (\sqrt{1 + \frac{1}{ n} } )}]  

=>    96.2 + (2.462 ) * 0.8 * (\sqrt{1 + \frac{1}{ 30} } )}]  

=>    98.2  

Considering second question

 Generally the sample is mathematically represented as

             \= x  = \frac{\sum x_i}{n}

=>           \= x  = \frac{ 9.8 + 10.2 + \cdots +9.6 }{7}  

=>           \= x  =  10    

Generally the standard deviation  is mathematically represented as

           \sigma =  \sqrt{ \frac{ \sum ( x_ i - \= x)}{n-1} }

=>        \sigma =  \sqrt{ \frac{ ( 9.8  -10)^2 +  ( 10.2  -10)^2 + \cdots + ( 9.6  -10)^2  }{7-1} }

=>        \sigma = 0.283

Generally the degree of freedom is mathematically represented as

      df =  n- 1

=>    df =  7- 1

=>    df =  6

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the t distribution table the critical value  of   at a degree of freedom of  is  

   t_{\frac{\alpha }{2} , 6 } =  2.447

Generally the margin of error is mathematically represented as  

      E = t_{\frac{\alpha }{2} , 6 } *  \frac{\sigma }{\sqrt{n} }

=>    E =2.447*    \frac{0.283 }{\sqrt{7} }

=>    E =0.2617

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>   10 -0.2617 <  \mu < 10 + 0.2617

=>   9.7383 <  \mu < 10.2617

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Offering 50 points really need help on homework
astra-53 [7]

i cant see the photo, it is black, and i cant see it can u post another one,

then i will help (:

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