6/7 !!!! the answer is 6/7
Step-by-step explanation:
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Answer:
Here are some answers
1. If you meant 6x = 0 then your answer is 0
2. If you meant 6 + x = 0 then your answer is -6
Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
The average r. of c. of a function f(x) on an interval [a,b] is:
f(b) - f(a)
--------------
b-a
You'll need to apply this to all four of the given functions.
First function: f(x) = x^2 + 3x
a= -2; b= 3
Then the ave. r. of c. for this function on this interval is:
18 - (-2) 20
------------------ = ---------- = 4. y increases by 4 for every unit increase in x.
3-(-2) 5
Do the same thing for the other 3 functions.
Then arrange your four results in descending order (greatest to least).
