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GenaCL600 [577]
3 years ago
10

C is the circumcenter of isosceles triangle ABD with vertex angle ABD. Does the following proof correctly justify that triangles

ABE and DBE are congruent? 1. It is given that triangle ABD is an isosceles triangle, so segments AB and DB are congruent by the definition of isosceles triangle. 2. It is given that is the circumcenter of triangle ABD, making segment BE a median 3. By the definition of perpendicular, angles AEB and DEB are 90°, so triangles ABE and DEB are right triangles. 4. Triangles ABE and DEB share side BE making it congruent to itself by the reflexive property 5. Triangles ABE and DBE are congruent by HL. E There is an error in line 1, segments AB and BD are given to be congruent. There is an error in line 2, segment BE should be a perpendicular bisector. There is an error in line 4, segment BE is not a shared side. The proof is correct​

Mathematics
1 answer:
sukhopar [10]3 years ago
3 0

Answer:

The answer is B

Step-by-step explanation:

Here is the evidence

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Solving a right triangle (round to the nearest tenth)
Inga [223]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for A

A = 180° - (90 + 46)° = 180° - 136° = 44°

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tan46° = \frac{opposite}{adjacent} = \frac{b}{23}

Multiply both sides by 23

23 × tan46° = b, thus

b ≈ 23.8 ( to the nearest tenth )

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cos46° = \frac{adjacent}{hypotenuse} = \frac{23}{c}

Multiply both sides by c

c × cos46° = 23 ( divide both sides by cos46° )

c = \frac{23}{cos46} ≈ 33.1 ( to the nearest tenth )

5 0
3 years ago
A rectangle is 2 4/5 M wide and 3 and 1/2 meters long what is its area
postnew [5]
2 4/5=14/5, 3 1/2=7/2
A=l*w
14/5*7/2=98/10
98/10=9 8/10, 9 4/5
A= 9 4/5

Answer: Its area is 9 4/5m^2
8 0
3 years ago
Read 2 more answers
Find the missing side (to 2dp)
nasty-shy [4]

Answer:

x = 17.74 cm

Step-by-step explanation:

tan 29 = x/32

0.5543 = x/32

x = 17.74 cm

4 0
3 years ago
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vlabodo [156]

Answer:

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4 0
2 years ago
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Translate ƒ(x) = |x| so that it's translated up by 5 units and vertically stretched by a factor of 3. What's the new function g(
zavuch27 [327]

Given:

The parent absolute function is

f(x)=|x|

To find:

The new function if the parent function is translated up by 5 units and vertically stretched by a factor of 3.

Solution:

The translation is defined as

g(x)=kf(x+a)+b                .... (1)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<k<1, then the graph compressed vertically by factor k and if k>1, then the graph stretch vertically by factor k.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

Parent function is translated up by 5 units. So, b=5

It is vertically stretched by a factor of 3. So, k=3.

There is no horizontal shift. So, a=0.

Now, putting k=3, a=0 and b=5 in (1), we get

g(x)=3f(x+0)+5

g(x)=3f(x)+5

g(x)=3|x|+5       [\because f(x)=|x|]

Therefore, the correct option is D.

5 0
3 years ago
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