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3 years ago

8

In a recent year the weather was partly cloudy 2/5 of the days.Assuming there are 365 days in a year how many days were partly c

loudy.

1 answer:

soldi70 [24.7K]3 years ago

7 0

Answer:

182.5

Step-by-step explanation:

i just divided 365 and 2 (I might be wrong tbh idek)

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Multiply and simplify. Assume that all variables are positive.

Oxana [17]

Answer:

multiply

Step-by-step explanation:

and then you are going to break it down

5 0

3 years ago

What is the solution to this inequality: -4(3x-5)<2(3x+4)

Delicious77 [7]

Answer:

x > 2/3

Step-by-step explanation:

-4(3x - 5) < 2(3x + 4)

Divide both sides by 2.

-2(3x - 5) < 3x + 4

Distribute on the left side.

-6x + 10 < 3x + 4

Subtract 3x from both sides.

-9x + 10 < 4

Subtract 10 from both sides.

-9x < - 6

Divide both sides by -9. Remember that when you divide both sides of an inequality by a negative number, the inequality sign changes direction.

x > (-6)/(-9)

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7 0

3 years ago

Please help, I will mark you brainiest, thank you’

stich3 [128]

Answer:

a

Step-by-step explanation:

6 0

3 years ago

Compare the triangles and determine whether they can be proven congruent by SSS, SAS, ASA, AAS, or HL. If not, type "NONE".

Komok [63]

Answer:

SAS

Step-by-step explanation:

6 0

3 years ago

If the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3

horrorfan [7]

Answer: The correct option is (B) 24 : 25.

Step-by-step explanation: Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.

We are to find the ratio of the area of R to the area of S.

Let 2x, 3x be the sides of rectangle R and y be the side of square S.

Then, according to the given information, we have

$\textup{Perimeter of rectangle R}=\textup{Perimeter of square S}\\\\\Rightarrow2(2x+3x)=2(y+y)\\\\\Rightarrow 5x=2y\\\\\Rightarrow \dfrac{x}{y}=\dfrac{2}{5}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Therefore, the ratio of the area of R to the area of S is

$\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.$

Thus, the required ratio of the area of R to the area of S is 24 : 25.

Option (B) is CORRECT.

6 0

4 years ago