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Semmy [17]
3 years ago
15

Please help this is due today!

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

The solution of \frac{1}{4}x \leq 2 is \mathbf{x\leq 8}

Graph of the solution is attached in the figure below.

Step-by-step explanation:

We need to the graph the solution of \frac{1}{4}x \leq 2

First we will solve to find value of x

\frac{1}{4}x \leq 2

Multiply both sides by 4

\frac{1}{4}x\times 4 \leq 2\times 4 \\x\leq 8

So, the solution of \frac{1}{4}x \leq 2 is \mathbf{x\leq 8}

Graph of the solution is attached in the figure below.

The graph contains both number line and on graph paper also.

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Which of the following changes will always be true for an exothermic process?
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Given that I no not see any explanation in the previos answer, I think you can benefit of this.

Exothermic refers only to the fact that the reaction releases energy in the form of heat when occurs. So, the enthalpy is higher at start and lower and the end.

Seen in this way, you can deduct that the change in enthalpy is negative, which is what the third option says. 
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3 years ago
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Please tell me if its A,B,C,D, or E
kow [346]

Answer:

A

Step-by-step explanation:

I did the math! and got 15

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You need at least 30 cubic feet of sand to fill a sand box. Each box contains 2.5 cubic feet of sand. Write and solve an inequal
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Step-by-step explanation:

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Combine like terms.<br><br> - 2/3p + 1/5 - 1 + 5/6p
DaniilM [7]

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Step-by-step explanation:

- 2/3p + 1/5 - 1 + 5/6p

When I combine like terms, I put them next to each other.

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Will Mark Brainlest Help Please ,,,, ​
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\\ \sf\longmapsto 2x+y=2

\\ \sf\longmapsto 2x=2-y

\\ \sf\longmapsto x=\dfrac{2-y}{2}\dots(1)

And

\\ \sf\longmapsto x+1=y+2

\\ \sf\longmapsto x=y+2-1

\\ \sf\longmapsto x=y+1

  • Put the value

\\ \sf\longmapsto \dfrac{2-y}{2}=y+1

\\ \sf\longmapsto 2-y=2(y+1)

\\ \sf\longmapsto 2-y=2y+2

\\ \sf\longmapsto 2-2=2y+y

\\ \sf\longmapsto 3y=0

\\ \sf\longmapsto y=\dfrac{0}{3}

\\ \sf\longmapsto y=\infty

  • Put in eq(1)

\\ \sf\longmapsto x=\dfrac{2-y}{2}

\\ \sf\longmapsto x=\dfrac{2-\infty}{2}

\\ \sf\longmapsto x=\dfrac{2}{2}

\\ \sf\longmapsto x=1

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