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maria [59]
3 years ago
12

This question has two parts. Syrilla sells homemade scarves for $4 each. Part A. Which equation could be used to find the number

of scarves, x, Syrilla needs to sell in order to earn $200?
Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

50 scarves

Step-by-step explanation:

1=$4

x=$200 we crisscross them and get

$4x=$200 we divide both side by 4 and we will get

×=50

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Which of the following represent(s) an equation of the line passing through the points A(5, 6) and B(4, 8). Select all that appl
andriy [413]

Answer:

The equations that represent the equation of the line are:

y = -2x + 16 ⇒ A

2x + y = 16 ⇒ D

y - 6 = -2(x - 5) ⇒ E

Step-by-step explanation:

The slope intercept form of the linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept (y at x = 0)

The formula of the slope is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ The line is passing through points (5 , 6) and (4 , 8)

∴ x_{1} = 5 and  x_{2} = 4

∴ y_{1} = 6 and  y_{2} = 8

- Substitute them in the formula of the slope to find it

∵ m=\frac{8-6}{4-5}=\frac{2}{-1}

∴ m = -2

- Substitute it in the form of the equation

∴ y = -2 x + b

- To find b substitute x and y in the equation by the coordinates

    of any point in the line

∵ x = 5 and y = 6

∴ 6 = -2(5) + b

∴ 6 = -10 + b

- Add 10 to both sides

∴ 16 = b

∴ y = -2 x + 16

∴ The equation of the line is y = -2x + 16

∴ A represents the equation of the line

∵ 2x + y = 16

- Subtract 2x from both sides

∴ y = -2x + 16

∴ D represents the equation of the line

∵ y - 6 = -2(x - 5)

∴ y - 6 = -2x + 10

- Add 6 to both sides

∴ y = -2x + 16

∴ E represents the equation of the line

The equations that represent the equation of the line are:

y = -2x + 16 ⇒ A

2x + y = 16 ⇒ D

y - 6 = -2(x - 5) ⇒ E

7 0
3 years ago
Based on the shortest leg of the triangle illustrated, if a similar triangle on the coordinate plane has its shortest leg define
GrogVix [38]

In a triangle ,shortest leg is located in the coordinate plane at B (-2,4) and  C(-6,0).

Distance between two points in  two dimensional plane is given by =\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2

BC= \sqrt{(-2 +6)^2+(4-0)^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt{2}

     = 4 × 1.414

     =   5.656

Let A (p,q), be the Third vertex of ΔA BC.There will be no single point. We can find the locus of point A.

Equation of line BC is :

\frac{y-0}{x+6}=\frac{4-0}{-2+6} \\\\ y= x +6

So,the third point that is Locus of point A ,will be no point lying on the line, →y= x +6.

Also, A Triangle is formed, when

Sum of two sides of triangle is greater than third side.

So,third point A will be such that,

1. AB +AC> BC

2. AB +BC> AC

3. AC +BC> AB

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Answer:

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Step-by-step explanation:

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Umnica [9.8K]
You do 4*9 and you will get 36 ways
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I have no clue how to solve this can someone help?
Alchen [17]

Answer:26

Step-by-step explanation:

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