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Grace [21]
3 years ago
8

Help please it’s one question! i’ll mark brainliest ❤️❤️l

Mathematics
1 answer:
olganol [36]3 years ago
5 0

Answer:

73.8

Step-by-step explanation:

10% of 82 is 8.2

82 - 8.2 = 73.8

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Fran has a poster that measures 3/4 square yard in area. The length of the poster is 1/3 yard. What is the width of the poster.i
Brums [2.3K]

Answer:

2 1/4 yards.

Step-by-step explanation:

Width = area / length

Width = 3/4 / 1/3

= 3/4 * 3

= 9/4

= 2 1/4 yards.

The width is actually the length!! but nvm.

3 0
3 years ago
Plz plz help me with this
Grace [21]
A) set them equal to 180° so it should be 180=5x+10 and x=34 plug it in and VRX=56° and WRV=124°
7 0
3 years ago
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
2 years ago
A square has<br> side<br> lengths of 3/4 in.<br> What is its area?
Leno4ka [110]

Hey there! :)

Answer:

A = 9/16 in².

Step-by-step explanation:

Use the formula A = s² to solve for the area where s = 3/4 in:

A = (3/4)²

A = 9/16 in².

7 0
3 years ago
Read 2 more answers
Someone help please I wi appreciate itttt so much
Dmitry_Shevchenko [17]

Answer:

65

Step-by-step explanation:

66

3 0
3 years ago
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