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2 years ago

Find the value of X round to the nearest degree

Mathematics

1 answer:

BARSIC [14]2 years ago

7 0

Check the picture below.

Make sure your calculator is in Degree mode.

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Ab (3a-5b) equals to?

Aleks04 [339]

Answer:

3a^2b-5ab^2

Step-by-step explanation:

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3 years ago

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Mamont248 [21]

Answer:

Yes and E

Step-by-step explanation:

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2 years ago

Derive the equation of the parabola with a focus at (0, −4) and a directrix of y = 4.

CaHeK987 [17]

Answer:

$y=-\frac{1}{16} x^2$

Step-by-step explanation:

Equation of parabola with focus at (0,-4) and directrix is $y=4$ .

We know that parabola is the locus of all the points such that the distance from fixed point on the parabola to fixed line directrix is the same.

The parabola is opening downwards.

Let any point on parabola is (x,y).

Distance from focus(0,-4) to (x,y) = $\sqrt{(x-0)^2+(y-(-4))^2}=|y-4|$

$\sqrt{(x-0)^2+(y-+4)^2}=|y-4|$

$(x-0)^2+(y+4)^2=(y-4)^2$

$(x)^2+(y+4)^2=(y-4)^2$

$x^2+(y^2+4y+4y+16)=y^2-4y-4y+16$

$x^2+y^2+8y+16=y^2-8y+16$

$x^2+16y^2=0$

$16y=-x^2$

$y=-\frac{1}{16} x^2$

6 0

2 years ago

Help plz WILL MARK Brainlyest

Alex17521 [72]

Answer:

11/12

Step-by-step explanation:

7/6= 14/12

8/6= 16/12

the number in between the two is 15/12 then it already shows you what to subtract by (4/12) so 15/12-4/12=11/12

8 0

2 years ago

1. The number of rabbits on an island is increasing exponentially.

Zina [86]

Answer:

There are approximately 114 rabbits in the year 10

Step-by-step explanation:

Exponential Growth

The natural growth of some magnitudes can be modeled by the equation:

$P=P_o(1+r)^t$

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

We are given two measurements of the population of rabbits on an island.

In year 1, there are 50 rabbits. This is the point (1,50)

In year 5, there are 72 rabbits. This is the point (5,72)

Substituting in the general model, we have:

$50=P_o(1+r)^1$

$50=P_o(1+r)\qquad\qquad[1]$

$72=P_o(1+r)^5\qquad\qquad[2]$

Dividing [2] by [1]:

$\displaystyle \frac{72}{50}=(1+r)^{5-1}=(1+r)^{4}$

Solving for r:

$\displaystyle r=\sqrt[4]{\frac{72}{50}}-1$

Calculating:

r=0.095445

From [1], solve for Po:

$\displaystyle P_o=\frac{72}{(1+r)^5}$

$\displaystyle P_o=\frac{72}{(1.095445)^5}$

$P_o=45.64355$

The model can be written now as:

$P=45.64355(1.095445)^t$

In year t=10, the population of rabbits is:

$P=45.64355(1.095445)^{10}$

P = 113.6

$P\approx 114$

There are approximately 114 rabbits in the year 10

5 0

3 years ago