Answer:
30
Step-by-step explanation:
Given :
Mean, m = 30 metric tons
Standard deviation (s) = 1.5 metric ton
Sample size, n = 4
Since the impact force in the test model is normally distributed, the shape of the sampling distribution will also be approximately normal with a mean equal to the mean of the test model.
Hence, the sample mean impact force will be equal to the population mean.
Therefore, sample mean = 30 ; population mean = 30
The angle of elevation is = 70° and the distance the airplane travelled in the air is = 17,557ft
<h3>Calculation of the distance travelled</h3>
- To calculate the angle of elevation of the airplane
tan x° = opposite/adjacent
where opposite = 16,500 feet
adjacent = 6,000 ft
tan x° = 16,500 / 6,000
tan x° = 2.75
X = arctan ( 2.75)
X = 70°
- To calculate the distance the airplane travelled in the air Pythagorean Theorem is used.
C² = a² + b²
C² = 16,500² + 6,000²
C² = 272250000 + 36000000
C² = 308250000
C= √308250000
C= 17,557ft
Learn more about Pythagorean Theorem here:
brainly.com/question/343682
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Answer:
Sin (E) = √74/(2√23)
Step-by-step explanation:
Reference Angle = E
Hypotenuse = 2√23
Adjacent = 3√2
Opposite = DC = √(2√23)² - (3√2)²) = √(4*23 - 9*2) = √(92 - 18) = √74 (pythagorean theorem)
Recall SOHCAHTOA.
Thus,
Sin (E) = opp/hyp
Sin (E) = √74/(2√23)
Answer:
33.6
you are welcome :)
Step-by-step explanation:
I am attaching a document showing the steps.