2 years ago

Fully factorize 6xy-2x+3z-9zy

Mathematics

1 answer:

Luden [163]2 years ago

3 0

Answer:

(2x−3z)(3y−1)

Step-by-step explanation:
6xy-2x+3z-9zy
2x(2xy-1)+3z-9zy
2x(-1+3y)+3z(1-3y)

(2x−3z)(3y−1)

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<h3>Answer:</h3>

A. $6x^2$ +-5x+14x+-35

$6x^2$ +9x-35

B. $5x^4+-3x^3+10x^3+-6x^2$

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Step-by-step explanation:

A. (3x*2x)+(3x*-5)+(7*2x)+(7*-5)

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$6x^2$ +9x-35

B. ( $x^2*5x^2$ )+( $x^2*$ -3x)+(2x $*5x^2$ )+(2x $*-3x$ )

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I hope this helps!

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