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2 years ago

Fully factorize 6xy-2x+3z-9zy

Mathematics

1 answer:

Luden [163]2 years ago

3 0

Answer:

(2x−3z)(3y−1)

Step-by-step explanation:
6xy-2x+3z-9zy
2x(2xy-1)+3z-9zy
2x(-1+3y)+3z(1-3y)

(2x−3z)(3y−1)

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Which expression is equivalent to 144^3/2

Tju [1.3M]

Answer:

$\large\boxed{144^\frac{3}{2}=1728}$

Step-by-step explanation:

$\sqrt[n]{a^m}=a^\frac{m}{n}\\\\144^\frac{3}{2}=144^{1\frac{1}{2}}=144^{1+\frac{1}{2}}\qquad\text{use}\ a^na^m=a^{n+m}\\\\=144^1\cdot144^{\frac{1}{2}}=144\sqrt{144}=144\cdot12=1728$

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3 years ago

Which fraction is greater than 3/5 4/6 6/12 3/8 4/10

Ulleksa [173]

Answer:

a.) 4/6

Step-by-step explanation:

3/5 = .6

4/6 = .666666666667

6/12= 0.5

3/8= .375

4/10= .4

8 0

3 years ago

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Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so

IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

Solution:

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

$14 \times c + 5 \times v=119$

14c + 5v = 119 ------- eqn 1

Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

$10 \times c + 10 \times v = 130$

10c + 10v = 130 -------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

Subtract eqn 2 from eqn 3

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

Substitute c = 6 in eqn 1

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0

2 years ago

(the stake is 14ft)

Kaylis [27]

Answer:

it‘s about

32.08 ft (if its not an answer choice try 32 or anywhere near that number)

Step-by-step explanation:

SO this is a simple example of triangles

We would need to find the heigh of the flagpole which is the leg of the triangle

The other side (14ft) is the 2nd leg of the triangle

And we know the hypotenuse is 35 ft

So we put that in Pythagorean Theroux and solve for the first missing leg

a^2+14^2=35^2

a^2+196=1225

a^2=1029

√1029 is about 32.08

So its about 32.08

5 0

2 years ago

4. Solve the equation for the given variable. For each step. Identity the property used to convert the equation. 22x + 11 = 4x -

Andrei [34K]

Answer:

x=-1

Step-by-step explanation:

5 0

2 years ago

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