We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458
If we assume that the selection is totally random, then all the students have the same<em> </em><em>probability </em><em>of being chosen.</em>
This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:
P = 11/16
For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).
Q = 10/15
The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:
Probability = P*Q = (11/16)*(10/15) = 0.458
So the probability that both students chosen for the duet are boys is 0.458
If you want to learn more, you can read:
brainly.com/question/1349408
Answer:
(1,4)
Step-by-step explanation:
Which ordered pair is a solution of the equation? y = 7 x − 3
a. (1,4) b. (-1,-4) c. both d. neither
Solution
y=7x-3
Solve by trying each ordered pair
a. (1,4)
x=1, y=4
Substituting the value of x and y into the equation
y=7x-3
4=7(1)-3
4=7-3
4=4
This is a true statement
b. (-1,-4)
x=-1, y=-4
Substitute the value into the equation
y=7x-3
-4=7(-1)-3
-4= -7-3
-4= -11
This is not a true statement
This true statement is when x=1 and y=4
So, the ordered pair (1, 4) is the solution
Answer:
at 2/3 seconds
Step-by-step explanation:
S1(t) = t³ + 2
Average speed, dS1/dt = 3t²
S2(t) = t²
Average speed, dS2/dt = 2t
The distance between the objects is
dS1/dt - dS2/dt
= 3t² - 2t
The time the distance between the two object is at minimum is when the distance is 0
That is, when
3t² - 2t = 0
t(3t - 2) = 0
t = 0 or 3t - 2 = 0
t = 0 or t = 2/3
Step-by-step explanation:
Area of circle =πr²
<h2>stay safe healthy and happy.</h2>