C
Let x be the cost of banana
Michael: 4x=2.72
Divide by 4 : x =.68
Tonya: 6x= 4.08
x = .68 divide by 6
Answer:
6 units
Step-by-step explanation:
(-4 , -10) ; (-4 , -4)
Distance = 
![= \sqrt{(-4-[-4])^{2}+(-4-[-10])^{2}}\\\\= \sqrt{(-4+4)^{2}+(-4+10)^{2}}\\\\=\sqrt{0+(6)^{2}}\\\\= \sqrt{36}\\\\= 6](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%28-4-%5B-4%5D%29%5E%7B2%7D%2B%28-4-%5B-10%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%20%5Csqrt%7B%28-4%2B4%29%5E%7B2%7D%2B%28-4%2B10%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B0%2B%286%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%20%5Csqrt%7B36%7D%5C%5C%5C%5C%3D%206)
Answer:
4x+2
Step-by-step explanation:
a= 2x - 3 and b= 2x+5
a+b = 2x-3 + 2x+5
Combine like terms
a+b = 4x+2
Answer:
- There is no significant evidence that p1 is different than p2 at 0.01 significance level.
- 99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)
Step-by-step explanation:
Let p1 be the proportion of the common attribute in population1
And p2 be the proportion of the same common attribute in population2
: p1-p2=0
: p1-p2≠0
Test statistic can be found using the equation:
where
- p1 is the sample proportion of the common attribute in population1 (
)
- p2 is the sample proportion of the common attribute in population2 (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the people from population1 (30)
- n2 is the sample size of the people from population2 (1900)
Then
≈ 2.03
p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.
99% confidence interval estimate for p1-p2 can be calculated using the equation
p1-p2±
where
- z is the z-statistic for the 99% confidence (2.58)
Thus 99% confidence interval is
0.533-0.704±
≈ -0.171 ±0.237 that is (−0.408, 0.066)
Answer: d
Step-by-step explanation: