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vivado [14]
2 years ago
15

Please fill out the information in the images

Mathematics
1 answer:
Gelneren [198K]2 years ago
7 0

The Areas of each of the composite shapes are;

1)  A = 30 m²

2) A = 20 yd²

3) A = 615.4 km²

4) A = 23 cm²

5) A = 168 m²

6) A = 86.3 m²

<h3>How to find the area of regular shapes?</h3>

1) Area of parallelogram = bh

A = 6 * 5

A = 30 m²

2) Area of Triangle = ¹/₂bh

A = ¹/₂ * 10 * 4

A = 20 yd²

3) Area of circle is;

A = πr²

A = 3.14 * 14²

A = 615.4 km²

4) Area of this composite figure is;

A = Area of Triangle - Area 0f rectangle

A = (¹/₂ * 13 * 10) - (7 * 6)

A = 65 - 42

A = 23 cm²

5) Area of composite figure is;

A = 2(¹/₂ * (16 + 8) * 3) + (16 * 6)

A = 72 + 96

A = 168 m²

6) Area of composite figure;

A = ¹/₂ * (15 + 8) * 7.5

A = 86.3 m²

Read more about Area of Regular Shapes at; brainly.com/question/25965491

#SPJ1

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Use the Binomial Theorem to expand the binomial<br> (d + 5b)3
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3 years ago
Carl puts $1.10 in his penny bank every day in the month of July (31 days) his total saving was 55.00 at the end of June. What’s
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6 0
3 years ago
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Takiya recorded the heights of two sets of plants, one set planted in the shade and one set planted in full sun. Her data are sh
marusya05 [52]

Question;

1) The shaded plants set has greater variability because more data is clustered around the median.

2) The sets are equally variable because the ranges of the data sets are equal.

3) The full sun plants set has greater variability because the IQR for full sun plants is greater.

Answer:

The correct option is;

3) The full sun plants set has greater variability because the IQR for full sun plants is greater

Step-by-step explanation:

To answer the question, we present the dot plot as follows;

Heights of Shaded plants (inches)

          0       4      3       2      0       0             1

0       1.5      2     2.5     3     3.5     4           4.5

We calculate the five numbers as follows;

Max = 4.5

Min = 2

1st quartile = (10+1)/4 th term = 2

2nd quartile (Median) = (10+1)/2 th term = 2.5

3rd quartile = 3×(10+1)/4 th term = 3

Interquatile range (IQR) = Q₃ - Q₁ = 3 - 2 = 1

Where:

Q₁ = 1st quartile

Q₃ = 3rd quartile

Heights of Full Sun plants

0     1      0      2      0       4         3

1.5   2    2.5    3     3.5     4        4.5

We calculate the five numbers as follows;

Max = 4.5

Min = 2

1st quartile = (10+1)/4 th term = 3

2nd quartile (Median) = (10+1)/2 th term = 4

3rd quartile = 3×(10+1)/4 th term = 4.5

Interquatile range (IQR) = Q₃ - Q₁ = 4.5 - 3 = 1.5

The interquartile range, IQR, is a measure of variability

Therefore, the full sun plants set has greater variability because the IQR for full sun plants is greater.

5 0
4 years ago
Read 2 more answers
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